Answer:
B. 
Step-by-step explanation:
Please find the attachment.
We have been given that line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8.
The probability that the first point is positioned on JL would be 
as there are total 10 points on JL as L is at point 8 and J is at point -2 so (8--2=8+2=10). Total number of points on the number line JM is (14--2=14+2=16)
The probability that second point is not placed on KL would be:
Therefore, our desired probability will and option B is the correct choice.
If you add a value to the outcome of the function (as in case a), you will just shift the graph up along the y-axis. Makes sense, right, since you're adding an extra 2 to the value you will plot on the y axis.
If you subtract (in this example) a value to the input of the function, you're actually "looking back" into the past of the graph (i.e., the left side). For example, for x=4 you're now plotting the value that used to be at x=1. So this shifts the graph to the right.
That may be confusing at first. But I hope with a little thought experiment, you get it.
Answer:
4x-2x+3y+6x+6y distributive property
4x-2x+6y+3y+6y commutative property of addition
8x+9y combine like terms
Step-by-step explanation:
I hope this helps!
Answer:
Cost to buy and run the first car for 5 years=$24000
Cost to buy and run the second car for 5 years=$26000
I think we should buy the first car, because It is cheaper to buy and maintain
Step-by-step explanation:
first car:
Cost $18000 to buy
Cost $100 to maintain each month
5years =5 x 12=60months
Cost to maintain for 60months=100x60=$6000
First car cost to buy and run over the 5 year period=18000+6000=$24000
Second car:
It cost $22400 to buy
Cost $60 to maintain each month
5years=60months
Cost to maintain for 60months is 60 x 60=$3600
Cost to buy and run over the second car for 5years is 22400+3600=$26000
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