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-BARSIC- [3]
3 years ago
6

All edges of a cube are expanding at a rate of 2 centimeters per second.

Mathematics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

  • Part a → dv/dt = 24 cm³/per second
  • Part b →  dv/dt = 1176 cm³/per second

Step-by-step explanation:

As all edges of a cube are expanding at a rate of 2 centimeters per second.

i.e ds/dt = 2 cm/s

The formula of volume of cube: V = s³

Differentiating the volume:

dv/dt = 3s²

Write ds/dt following derivative of volume

dv/dt = 3s² ds/dt

plug in the value: ds/dt = 2 cm/s

dv/dt = (3s²) (2)

dv/dt = 6s²

Given the edge is 2cm.

so plug in the value: s=2

dv/dt = 6s²

          = 6(2)²=6(4)=24 cm³/per second

SIMILARLY,

When the edge is 14cm

dv/dt = 6s²

plug in the value: s=14

dv/dt = 6s²

         = 6(14)²=6(196)=1176 cm³/per second

Thus,

  • Part a → dv/dt = 24 cm³/per second
  • Part b →  dv/dt = 1176 cm³/per second
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