Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 2x - 13
a = 1 b = -2 c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74
Answer:
A) I only
Step-by-step explanation:
median = 25
mean = 36
Plot for given distribution is shown in fig attached below. mean is shown with red block and median with green block. plot is skewed to the left and there is no outlier.
X is 35, if you follow the rules of alternate angles
The mode for this question is <u>0</u>
<h3>Mode</h3>
In a set of numbers, the mode is the number that occurs most often. In other words, it measures how frequently a particular number occurs within a set of numbers. It is a type of average, like its counterparts, the median and mean.
To find the mode of a set of numbers,
- List the set of numbers in ascending or descending order, including any duplicates
- Count the number of times each number in the set of numbers occurs. The number that occurs the highest number of times is the mode of the set of data
A = 5 + t
t + 3 = 2/3a
t + 3 = 2/3(5 + t)
t + 3 = 10 + 2t / 3
3t + 9 = 10 + 2t
t = 1
a = 5 + 1
a = 6
