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shusha [124]
3 years ago
6

Whoever helps with number 10 gets brainliest answer and 10 points :)

Mathematics
2 answers:
Irina18 [472]3 years ago
8 0
Before working with any range of numbers you need to put them from smallest to largest, so it would be: (15, 43, 46, 48, 53, 69, 90).


To find the mean you add up all the numbers and divide by how many numbers there are in the sequence. (In this case there are 7). 
(15+43+46+48+53+69+90)/7= 52
Mean= 52

To find the median you find the middle most number of the sequence, which is 48. If you need help doing this, all you do is cross out one number at a time at the beginning then at the end, continuously.
Median= 48

To find the mode of this sequence you see which number appears the most often, but in this case there isn't a number that appears more than once.
Mode= no mode 

Finding the range is pretty simple, you subtract the largest number by the smallest number (90-15)
Range= 75

Hope this helped!! :)
madreJ [45]3 years ago
3 0
10) Mean 52 Mode No Mode (all shown only once) Median 48 Range 75
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Answer:

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6 0
3 years ago
Find the 2nd and 3rd term of the sequence -7, _, _, -22, -27
melomori [17]

Answer:

-12,-17

Step-by-step explanation:

I just added five to each of the numbers

4 0
4 years ago
What is the area of a rectangle with length 112 foot and width 34 foot?
Nastasia [14]

Answer:

<u>3808ft²</u>

Step-by-step explanation:

Formula: A=L×W

<u>A=</u> area

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<u>W=</u> width

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8 0
3 years ago
Graph the inequality Y&gt; |x-7| +1
Alexus [3.1K]
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3 years ago
Item 1 The value of a car is $23,000. It loses 11.1% of its value every year. Find the approximate monthly decrease in value. Ro
IrinaK [193]

Answer:

<h2>$212.8</h2>

Step-by-step explanation:

If the car loses 11.1% per year, we need to calculate how much money is that:

23,000\frac{11.1}{100} = 2,553.; this value is the lost per year.

Now, in order to calculate this loss per month, we divide it by 12:

\frac{2553}{12} =212.75

Hence, the monthly value decrease is $212.8, rounding it to the tenth.

7 0
4 years ago
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