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3 years ago

Attached below...………………………...tec

Mathematics

2 answers:

lisov135 [29]3 years ago

5 0

Root 3................................

r-ruslan [8.4K]3 years ago

4 0

Answer:

$1\sqrt{3}$

Step-by-step explanation:

This is the answer because in a 30-60-90 triangle each side has a different formula to find it, the side across from angle 60 is half the hypotenuse and root 3

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PLZ HALP!! I need this to be done ASAP!!

lyudmila [28]

4.5(4-x) + 36 = 202 - 2.5(3x + 28)

Distributive property

18 - 4.5x + 36 = 202 - 7.5x - 70

Combine like terms

-4.5x + 54 = -7.5x + 132

Add 7.5x to both sides

3x = 78

Divide both sides by 3

x = 26

3 0

3 years ago

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .

The equation for a sphere of radius $r$ and center $\left(x_0,\, y_0,\, z_0\right)$ would be:

$\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2$ .

In this case, the equation would be:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2$ .

Simplify to obtain:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56$ .

Expand the squares and simplify to obtain:

$x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ .

8 0

3 years ago

In which case is it possible to create exactly one triangle with the given measures?

avanturin [10]

Choices "a" and "c" will form triangles

6 0

3 years ago

Please help me answer this question mathematicians

Damm [24]

Answer:

6.5e^(i·(-157.38°)) ≈ 6.5e^(-2.7468i)

Step-by-step explanation:

A suitable calculator can find the value of this ratio for you.

((2+3i)/(1-i))² = -6 -2.5i ≈ 6.5∠-157.38° ≈ 6.5e^(-2.7468i)

The second attachments shows the calculator set to radian mode for the angle measure.

6 0

2 years ago

Calculate the area of triangle ABC with altitude CD, given A(−7, −1), B(−1, 5), C(0, 0), and D(−3, 3)

Snezhnost [94]

Answer:

A=25 (Rounded)

Step-by-step explanation:

The first step is to find the length of BA which is the base, then you have the find the length of CD, the hight.

To find the distance, you need to use the distance formula which is

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$ (It does not matter if A is x1 or is B is x1, it just has to remain consistent)

I am going to first find BA

$d=\sqrt{\left({-7}-{-1}\right)^{2}+\left({-1}-{5}\right)^{2}}$

Next, subtract accordingly

$d=\sqrt{\left({-7}+{1}\right)^{2}+\left({-1}-{5}\right)^{2}}$

$d=\sqrt{\left({-6}\right)^{2}+\left({-6}\right)^{2}}$

Once you do that, you want to square -6 and -6 which will give you

$d=\sqrt{\left({36}\right)+\left({36}\right)}$

Now add 36 with 36 which will leave you with

$d=\sqrt{{72}}$

Do that same thing for CD. If you did it right, you should be left with

$d=\sqrt{{18}}$

to find the area of a triangle, you must use the formula

$A=\frac{B*H}{2}$

The Base is $\sqrt{{72}}$ (BA) and the Hight is $\sqrt{{18}}$ (CD). substitute to get

$A=\frac{\sqrt{{72}}*\sqrt{{18}}}{2}$

Multiply the Base by the Hight to get

$A=\frac{\sqrt{{1,296}}}{2}$

Divide 1,296 by 2 to get

$A=\sqrt{{648}}$

Which is equal to

$A=25.455844122715710878430397035775$

Rounding it to the nearest whole number you get

A=25

Hope this helps. Feel free to ask any follow-up questions.

Have a good day! :)

6 0

3 years ago