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2 years ago

10

Hi please help! i’m somehow stuck on this

1 answer:

pochemuha2 years ago

6 0

Answer:p=12

Step-by-step explanation:

(9p)+(p+21)+(p+27)=180

9*12=108

12+21=33

12+27=39

108+33+39=180

so p=12

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Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A

iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

$\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA$

7 0

2 years ago

Select the correct answer.

Tpy6a [65]

Answer:

your answer is D.

Step-by-step explanation:

Using sine will give you 3*square root of 3

3 0

2 years ago

Read 2 more answers

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

2 years ago

I NEED HELP!!!!!!!!!!!!!

Igoryamba

Answer:

c+d

Step-by-step explanation:

c as the liters of water in the bucket, and d as the liters of water the jar more.

Together, you have to use addition to answer the question.

Note:

Pls, notify me if my answer is incorrect for the other users that will see this response. Thank you. Have a wonderful rest of your day!

<em>-kiniwih426</em>

4 0

2 years ago

Read 2 more answers

∠ABD and ∠BDE are supplementary. Find the measures of both angles.

Gnom [1K]

Supplementary means that the angles have to add up to 180, so you have your equation.

180=5x+17x-18

198=22x

x=9

Then to find the measures of the angles, you plug x back in.

m∠ABD=5(9)=45 degrees

m∠BDE=17(9)-18=153-18=135 degrees

5 0

3 years ago