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Ad libitum [116K]
2 years ago
11

What is wrong with the equation? 3 x−5 dx = x−4 −4 3 −1 = 20 81 −1 There is nothing wrong with the equation. f(x) = x−5 is conti

nuous on the interval [−1, 3] so FTC2 cannot be applied. The lower limit is less than 0, so FTC2 cannot be applied. f(x) = x−5 is not continuous on the interval [−1, 3] so FTC2 cannot be applied. f(x) = x−5 is not continuous at x = −1, so FTC2 cannot be applied.
Mathematics
1 answer:
Alchen [17]2 years ago
7 0

Answer:

ggggg

Step-by-step explanation:

You might be interested in
-4x - 84 = 2x + 24 <br> ??????
yarga [219]

Answer:

x= -54

Step-by-step explanation:

-4x - 84 = 2x + 24

-4x + 2x= 24 + 84

-2x= 108

x= 108 ÷ (-2)

x= -54

5 0
3 years ago
A farm has 15 rows of fruit trees with 7 trees in each row. The last 4 rows of trees are cherry trees. The remaining trees are o
siniylev [52]

Answer:

Total number of orange trees = 77 trees

Step-by-step explanation:

Given:

Total number of rows = 15

Total number of cherry rows = 4

Number of trees in each rows = 7

Find:

Total number of orange trees

Computation:

Total number of orange trees = [Total number of rows - Total number of cherry rows][Number of trees in each rows]

Total number of orange trees = [15 - 4]7

Total number of orange trees = [11]7

Total number of orange trees = 77 trees

6 0
2 years ago
The frequency of the musical note E3 is about 164.81 Hz.
laiz [17]
A perfect fifth above a note has a frequency ratio of 3 to 2.
Therefore, we can set the proportion:
164.81 : x = 2 : 3

which gives:
x = <span>164.81 </span>× 3 ÷ 2
   = 247.21

Hence, the perfect fifth above E₃ will have a frequency of 247.21Hz which corresponds to a B₃.
6 0
3 years ago
Read 2 more answers
What is the equation in standard form of the line that passes through the point (1, 24) and has a slope of -0.6.
lana [24]

Answer:

0.6x+y=24.6

Step-by-step explanation:

y-y1=m(x-x1)

y-24=-0.6(x-1)

y=-0.6x+0.6+24

y=-0.6x+24.6

y-(-0.6x)=24.6

y+0.6x=24.6

0.6x+y=24.6

6 0
3 years ago
The density of acetic acid is 1.05 g/mL. What is the volume of 327 g of acetic acid?
steposvetlana [31]
This is a chemistry problem btw. But, either way, the formula for density is mass per unit of volume. To solve for volume, bring the D over to get M/D = V
(327g)/(1.05g/ml) is the equation. Grams cancel and you’re stuck with 311.428571mL. That isn’t your answer tho, because that isn’t the right amount of sig figs. We have two figs at the least so the right answer would be 311.42 or 311.43mL. We want it in scientific notation, so move the decimal place between 3 and 1. That’s two spots to the left, so the power would be 2. C is your right answer

My chem professor told me to round to even instead of rounding up all the time. Either way, the hundreds place is always a percent error of plus or minus 0.01
7 0
2 years ago
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