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balandron [24]
3 years ago
5

The radius of the circle above is 36 mm. What is the circumference of the circle? (Use = 3.14.)

Mathematics
1 answer:
Vsevolod [243]3 years ago
4 0

Answer:

the answer is poop poop poop poop poop poop poop poop poop poop poop poop poop poop poop poop poop poop poop pie poop poop poop poop poop poop poop poop poop in your mouth poopy in your mouth poopy in your mouth poopy in your mouth poop in your mouth poopy in your mouth poopy poopy in your mouth poopy in your mouth to be poopy in your mouth poopy in your mouth to be poopy in your mouth poopy in your mouth again your mouth in your mouth

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What are the equations that have the same solutions as 3x-12=24 between
Effectus [21]

Answer:

ddqsc

Step-by-step explanation:

rdfgrrffferrrrrddr

5 0
2 years ago
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What is the value of the expression? Drag and drop the answer into the box to match the expression. 0.9(1/2−2)+0.6
mrs_skeptik [129]
Should be, -0.7, if you follow PEMDAS
6 0
3 years ago
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-4x + 11y = 15<br> X = 2y <br><br> Solve using substitution <br><br> X = <br><br> Y=
Virty [35]
-4(2y)+11y=15, -8y+11y=3y=15: y=5

X=2(5)=10

To check your work -4(10)+11(5)=15
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8 0
2 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
Round 26 to its greatest place value
Crank
26 27 28 29 30 so 25 24 23 22 21---so 30 is the awnser
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3 years ago
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