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JulijaS [17]
3 years ago
7

Diagram 7 shows a regular hexagon UVWXYZ.

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0

Answer:

option d is the correct answer

Step-by-step explanation:

use formula for finding sum of all interior angles of regular polygon i.e. (n-2)×180 where n is no of sides of regular polygon then divide it by no. of sides of regular polygon to find measure of one angle of regular polygon and then subtract it from 180° to find the answer

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The length of Marshall's poster is 2 times its width. If the perimeter is 72 inches, what is the area of the poster?
lesya [120]
x-width\\2x-length\\\\2x+2\cdot2x=72\\2x+4x=72\\6x=72\ \ \ \ |:6\\x=12\\\\2x=2\cdot12=24\\\\Area=24\cdot12=288\ in^2
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3 years ago
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hram777 [196]

Answer:

a) x = -10

b) x = 7

Step-by-step explanation:

a)

2(x + 3) = x - 4

2x + 6 = x - 4

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x = -10

b)

4(5x - 2) = 2(9x + 3)

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$0.30 per orange

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3 years ago
If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm
natulia [17]

Answer:

<h2>16kg</h2>

Step-by-step explanation:

 This problem is borers on elasticity of materials.

according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

F= ke

where F is the applied force in N

          k is the spring constant N/m

          e is the extension in meters

Given data

mass m= 24kg

extensnion=15cm in meters= \frac{15}{100}= 0.15m

we can solve for the spring constant k

we also know that the force F = mg

assuming g=9.81m/s^{2}

therefore

24*9.81=k*0.15\\235.44=k*0.15\\k=\frac{235.44}{0.15} \\k=1569.6N/m\\

We can use this value of k to solve for the mass that will cause an extension of  10cm= 0.1m

x*9.81=1569.6*0.1\\\\x= \frac{156.96}{9.81} \\\x= 16kg

5 0
3 years ago
What is the volume of the composite figure? Round your answer to the nearest hundredth. Use 3.14 for π.
Reil [10]

Answer:

<em><u>263.76</u></em><em><u> </u></em><em><u>in</u></em><em><u>^</u></em><em><u>3</u></em>

VOLUME OF FIGURE=VOL.OF CONE+VOL.OF CYLINDER +VOL.OF HEMISPHERE

=(1/3×3.14×3×3×4)+(3.14×3×3×6)+(2/3×3.14×3×3×3)

=37.68+169.56+56.52

=263.76in^3

7 0
3 years ago
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