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Nostrana [21]
3 years ago
5

What are factors of 30

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0
1,2,3,5,6,10,15,30 because by looking at the number at the ones place, when it is 0 or an odd number, it could be divided by 2. When the places are added together and when it is divisible by 3, it is the factor of 3. Also, when there are 2 and 3 as a factor, it is also divisible by 6.
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The zero-product principle states that if AB = 0, then
s2008m [1.1K]

A = 0 (or) B = 0

Solution:

The zero product principle is most probably used to solve a quadratic equation by factoring the factors.

Let us know the definition of zero product principle.

Zero product principle:

The zero product principle states that if the product of two factors is zero then  at least one of the factors must be zero.

This means that if AB = 0, then A = 0 (or) B = 0.

Hence, The zero-product principle states that

if AB = 0, then A = 0 (or) B = 0.

8 0
3 years ago
Solve the equation using the method that seems appropriate.
Lera25 [3.4K]
The answer is x=-5.5 . 2x-3 = 4x+8 . subtract 2x from both sides and then subtract 8 from both sides and get -11=2x . then divide both sides by 2 to get . -5.5=x
8 0
2 years ago
Use the distance to find the distance between the points A (-3,7 and B (-2,5).
Eva8 [605]

Step-by-step explanation:

1 2 3 4 5

wa

6 0
2 years ago
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
Write 2 1/16 as a decimal
devlian [24]

Answer:

2.0625

Step-by-step explanation:

2+1/16

= 2.0625

= 206.25%

6 0
3 years ago
Read 2 more answers
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