Question

A restaurant interest survey of 230 citizens in a town showed that 80 want a new Chili's, 120 want a new Red Lobster, and 20 want both. Determine the probability that:
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Answer 1

The right solution to the given question is "$\frac{2}{23}$", "$\frac{6}{23}$" and "$\frac{5}{23}$".

According to the question,

• $a+b+c+d = 230$
• $b = 20$
• $a+b = 80$

By putting the value of "b", we get

• $a+20=80$

                $a = 80-20$

                $a = 60$

• $b + c=120$

By putting the value of "b", we get

      $20+c=120$

              $c = 120-20$

              $c = 100$

• $d = 230-60-100-20$

By putting the values of "a", "b", "c" and "d", we get    

       $d = 50$

(a)

P(both Chili's and Red lobster),

= $\frac{b}{a+b+c+d}$

= $\frac{2}{23}$

(b)

P(only chili's),

= $\frac{a}{a+b+c+d}$

= $\frac{6}{23}$

(c)

P(neither),

= $\frac{d}{a+b+c+d}$

= $\frac{5}{23}$

Learn more about probability here:

brainly.com/question/24269622

Answer 2

Answer:

2/23

6/23

5/23

Step-by-step explanation:

60 only want chilis

20 wants both

100 only want red lobster

50 want neither