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anastassius [24]

3 years ago

15

HELP PLZZ!!!!!!!! Look at this equation: 2 H2 + O2 --> 2 H2O. Why isn't there any coefficient in front of oxygen?

2 answers:

Nostrana [21]3 years ago

7 0

All of them are correct

HACTEHA [7]3 years ago

4 0

Answer:

D. All of these

Step-by-step explanation:

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Anettt [7]

All your doing is multiplying area, so just foil each term. The answer you will get is 24w^3-30w^2+17w-6

5 0

3 years ago

Shelly hopped onto her bicycle and pedaled to the park at 14 miles per hour. Then she whizzed back at 20 miles per hour. If the

Nataly_w [17]

The park was 28 miles away

4 0

3 years ago

Write decimal that is 10 times as greater as 0.009. please help

lawyer [7]

You multiply 0.09 by 10 and that'd equal 0.09. A number 10 times greater then 0.009 is 0.09.

3 0

3 years ago

Consider two functions f and g on [1, 8] such that integral^8_1 f(x) dx = 9, integral^8_1 g(x) dx = 5, integral^8_5 f(x) dx = 4,

Gelneren [198K]

I'll abbreviate the definite integral with the notation,

$I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx$

We're given

$I(f,1,8)=9$
$I(g,1,8)=5$
$I(f,5,8)=4$
$I(g,1,5)=3$

Recall that the definite integral is additive on the interval $[a,b]$ , meaning for some $c\in[a,b]$ we have

$I(f,a,b)=I(f,a,c)+I(f,c,b)$

The definite integral is also linear in the sense that

$I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)$

for some constant scalars $k,\ell$ .

Also, if $a\ge b$ , then

$I(f,a,b)=-I(f,b,a)$

a. $I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}$

b. $I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}$

c. $I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}$

d. $I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}$

e. $I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}$

f. $I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}$

4 0

3 years ago

Please I really need help with this

Delvig [45]

Answer:

Step-by-step explanation:

㏒ 3+㏒(x+2)=1

㏒3(x+2)=1

3(x+2)=10^1

3x+6=10

3x=10-6=4

x=4/3

so A

3.

$log_{2}x+log_{2}(x+2)=3\\or~log_{2}[x(x+2)]=3\\x(x+2)=2^3\\x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x+4)(x-2)=0\\x=2,-4\\x=-4 ~is~an~extraneous~solution.\\B$

6 0

3 years ago