We know that
P(winning) = 1/38
P(losing) = 1-1/38 = 37/38
Expected value = 175*1/38 - 5*37/38
175/38 - 185/38 = - 10/38 =-$0.2632
the answer part A) is
The player's expected value is -$0.2632 ( is losing)
b) <span>if you played the game 1000 times, how much would you expect to lose?
</span>-$0.2632*1000=-$263.20
the answer Part B) is $263.20
Answer:
option a 21 is the right answer
Step-by-step explanation:
7/12.36
12 into 3 is 36
so 12 1's are and 12 3's are
now it'll become 7 into 3
which is 21
therefore 21 is the answer
Answer:
0.3721 or 37.21%
Step-by-step explanation:
P(I) = 0.60; P(II) = 0.40;
P(not defective I) = 0.90; P(not defective II) = 0.80
The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

The probability is 0.3721 or 37.21%.
Answer:
5
Step-by-step explanation:
I subtracted