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3 years ago

20 Point plus brainlest whoever answer first and GET IT RIGHT

Mathematics

2 answers:

Umnica [9.8K]3 years ago

6 0

4, 64b, 3

i dont know how to type square root but those are the blanks in order

hope this helps :)

muminat3 years ago

4 0

Answer:

4√(64b) ^ 3

The 4 is the root not multiplied

Step-by-step explanation:

The 64b is inside the radical

The 4 is the root we are taking so it goes on the left of the radical

We are raising 64b to the third power so it is the exponent to the right

4√(64b) ^ 3

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The real number square root over 23 belongs to which set of numbers? irrational numbers integers rational numbers whole numbers

weqwewe [10]

Irrational numbers
Hope this helps

7 0

3 years ago

PLEAWSE HELP GIVING BRAINLIEST!!!<br> PLEASEEEEEEEee

frutty [35]

Answering so the person above can be marked brainliest

4 0

3 years ago

B) 5z - 1<br> when z = 6<br> 2

gogolik [260]

Answer:

309

Step-by-step explanation:

5z-1, z=62

5(62)-1

310 - 1

309

7 0

3 years ago

X^3+y^3=???????????????

omeli [17]

Answer:

Well since we don't know what X or Y is, then we can't answer this question.

Step-by-step explanation:

6 0

3 years ago

Coefficiants of (2x+y)^4

sattari [20]

By the binomial theorem,

$(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

Then the coefficients of the $x^{4-k}y^k$ terms in the expansion are, in order from $k=0$ to $k=4$ ,

$\dbinom 402^{4-0}=1\cdot2^4=16$

$\dbinom412^{4-1}=4\cdot2^3=32$

$\dbinom422^{4-2}=6\cdot2^2=24$

$\dbinom432^{4-3}=4\cdot2^1=8$

$\dbinom442^{4-4}=1\cdot2^0=1$

3 0

3 years ago