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VikaD [51]
3 years ago
8

2. What are the current values and appreciation rates of the two coins you selected?

Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0

Step-by-step explanation:

You should pick the coin that is cheap but one that also has a high inflation value. You should graph out the rate of increase per year to see if the coins are worthy of investing upon

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Which transformation have been preformed on a graph of f(x)=x2 to obtained the graph of g(x) =-3(x+1)2-4?
avanturin [10]

Horizontal shift because g(x)=f(x+1) 1 unit left

Vertical shift because g(x)=f(x+1)-4 4 units down

Reflected across x-axis because g(x)=-f(x)

Vertically stretched because g(x)=3(f(x))

Step-by-step explanation:

We need to identify which transformation have been preformed on a graph of f(x)=x2 to obtained the graph of g(x) =-3(x+1)2-4?

Rules for transformation:

Horizontal shift: depends on the value h

if g(x)=f(x+h) then: the graph is shifted left h units

if g(x)=f(x-h) then: the graph is shifted right h units

Vertical Shift: depends on the value k

if g(x)=f(x)+k then: the graph is shifted up k units

if g(x)=f(x)-k then: the graph is shifted down k units

Reflection:

if g(x)=-f(x) then graph is reflected at x-axis

if g(x)=f(-x) then graph is reflected at y-axis

Vertical Stretch:

if g(x)=c.f(x) then graph is vertically stretched.

In the given question:

f(x)= x^2

g(x)=-3(x+1)^2-4

Applying the above rules of transformation:

The graph is:

Horizontal shift because g(x)=f(x+1) 1 unit left

Vertical shift because g(x)=f(x+1)-4 4 units down

Reflected across x-axis because g(x)=-f(x)

Vertically stretched because g(x)=3(f(x))

Keywords: Transformations

Learn more about Transformations at:

  • brainly.com/question/2415963
  • brainly.com/question/3779181
  • brainly.com/question/5563823
  • brainly.com/question/9381523

#learnwithBrainly

7 0
3 years ago
The kwon family has a rainwater catchment system they use to water their garden. the storage tank is 72 inches deep. three hours
atroni [7]

The tank is filling at the rate of (58-36) in/(5-3 h) = 22/2 = 11 in/h.

72-58 = 14 inches more to fill

<span>
The remaining 14 inches will be filled in
14 /11  = 1.27 , round to 1.3 hours</span>

 so total time would be 5 +1.3 = 6.3 hours


4 0
3 years ago
NEED HELP ASAP<br> Given G (-6,5) and H (2, -7), what is the length of GH
lesya692 [45]

\bold{\huge{\green{\underline{ Solution }}}}

\bold{\underline{ Given}}

  • <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

\bold{\underline{To  \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

\bold{\underline{Let's \:  Begin :- }}

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}

  • <u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}

\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}

\sf{Distance\:GH=√(-8)^2+(12)^2}

\sf{ Distance \:GH =√64 + 144 }

\sf{ Distance \:GH =√ 208}

\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}

\sf{ Distance \:GH = 4√13}

\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}

3 0
2 years ago
How many 'faces' are on this square pyramid?​
qaws [65]

Answer:

5

Step-by-step explanation:

There are 5 faces on a square pyramid

7 0
3 years ago
Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s
ozzi

Answer:

10.9\ \text{m/s}^2

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

\mu = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2

La aceleración del bloque es 10.9\ \text{m/s}^2.

8 0
3 years ago
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