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tatuchka [14]
3 years ago
6

Select the correct answer.

Biology
2 answers:
V125BC [204]3 years ago
6 0
I’m pretty sure it is B
Mashutka [201]3 years ago
5 0

Answer:

b!!!!!!!!¡¡!!!!!!!!!!!!

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Genetic linkage mapping for a large number of families identifies 4% recombination between the genes for Rh blood type and ellip
Cloud [144]

Answer:

0.2404

Explanation:

The genes R/r and E/e are linked and there is 4% recombination between them.

<u>The possible genotypes and phenotypes are:</u>

  • RR or Rr: Rh+ blood type
  • rr: Rh- blood type
  • EE or Ee: elliptocytosis
  • ee: normal red blood cells

Tom and Terri each have elliptocytosis (they are E_), and each is Rh+ (they are R_).

Tom's mother has elliptocytosis (E_) and is Rh- (rr), so she has the genotype Er/_r. His father is healthy (ee) and has Rh+ (R_), so he has the genotype eR/e_. Tom must have inherited his E allele from his mother and his R allele  from his father, so he has the genotype eR/Er.

Terri's father is Rh+ (R_) and has elliptocytosis (E_), while Terri's mother is Rh- (rr) and is healthy (ee) with the genotype er/er. Terry could only receive the chromosome <em>er </em>from her mother, and because she is heterozygous for both genes the dominant alleles were both received from her father. Terri's genotype is ER/er.

The frequency of recombination is 4%, so 4% of the produced gametes will be recombinant. There are two possible recombinant gametes, so each will appear 2% of the times (a frequency of 0.02).

<u />

<u>Tom will produce the following gametes:</u>

  • eR, parental (0.48)
  • Er, parental (0.48)
  • er, recombinant (0.02)
  • ER (recombinant (0.02)

<u>Terri will produce the following gametes:</u>

  • ER, parental (0.48)
  • er, parental (0.48)
  • Er, recombinant (0.02)
  • eR, recombinant (0.02)

A child Rh- with elliptocytosis has the genotype rrE_. This can happen from the independent combination of the following gametes from Tom and Terri respectively:

  • Er (0.48) × er (0.48) = 0.2304 Er/er
  • Er (0.48) × Er (0.02) = 0.0096 Er/Er
  • er (0.02) × Er (0.02) = 0.0004 er/Er

And the total probability of having a rrE_ child will be 0.2304 + 0.0096 + 0.0004 = 0.2404

6 0
3 years ago
How are the competition and the commensalism relationships similar
KiRa [710]

Answer:

Predation and Competition. Two of the main ways that populations interact with one another is by competition and by predation. In competition, individuals seek to obtain the same environmental resource. In predation, one population is the resource of the other.

Explanation:

6 0
3 years ago
Explain how interactions can be both beneficial and harmful to the organisms in a community.
marshall27 [118]
The interactions can be harmful because they can poison the organisms and they can be helpful because they can help improve the organisms surroundings ex. food/ water supply.
3 0
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The goal of invaders such as bacteria and viruses is to __________.
kkurt [141]
Use a human body as a home.
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Termination of the abdomen in which the anus is located *
densk [106]

Answer:

Telson

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its the last segment of the abdomen.

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