To get that, you have to multiply the both numbers, which is 24*12=288
Answer:
The answer is A.
Step-by-step explanation:
Firstly, you have to take out the common terms for this expression. In this expression, the common terms ard 2 and m :
Next you have to factorise the brackets :
So the final answer is :
This question s incomplete, the complete question is;
The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.
There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour
Answer:
The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Step-by-step explanation:
Given the data in the question;
let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively
so
x + y = 55 ----------------equ1
x = 55 - y ------------------qu2
also
15x + 30y = 1050
x + 2y = 70 --------------equ3
input equ2 into equ3
(55 - y) + 2y = 70
- y + 2y = 70 - 55
y = 15
input value of y into equ1
x + 15 = 55
x = 55 - 15
x = 40
Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Answer:
I'm sorry but what is the question?
Step-by-step explanation:
Answer:
k = -1/240
Step-by-step explanation:
to evaluate the value of k in the expression 1/3k+80=1/2k+120
we have
1/3k+80=1/2k+120
collect the like terms for easy evaluation
1/3k - 1/2k = 120 -80
1/3k - 1/2k = 40
find the lcm
2 - 3/6k = 40
-1/ 6k = 40
cross multiply
6k x 40 = -1
240k = -1
divide both sides by 240
240k/240 = -1/ 240
k = -1/240
therefore the value of k in the expression 1/3k+80=1/2k+120 is equals to -1/240
