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igomit [66]
2 years ago
11

What were the dimensions of the original photo? 4 inches by 4 inches 6 inches by 6 inches 10 inches by 10 inches 12 inches by 12

inches
Mathematics
1 answer:
alexandr402 [8]2 years ago
4 0

Answer:

6 inches by 6 inches

Step-by-step explanation:

Area of the square = 256 inches ²

Given equation:

(x + 10)² = 256

Where,

x = side measure of the original square

(x + 10)² = 256

(x + 10)(x + 10) = 256

x² + 10x + 10x + 100 = 256

x² + 20x + 100 = 256

x² + 20x + 100 - 256 = 0

x² + 20x - 156 = 0

Solve the quadratic equation by factorization

Find two numbers whose product is -156 and sum is 20

The numbers are -26 and 6

x² + 26x - 6x - 156 = 0

x(x + 26) - 6(x + 26) = 0

(x + 26) (x - 6) = 0

x + 26 = 0 or x - 6 = 0

x = -26 or x = 6

Side length of a square can not be negative

Therefore,

x = 6 inches

6 inches by 6 inches

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In the equation y=a(x-h)^2+k, the "k" translates the parabola in what manner?
stellarik [79]

Answer:

k is the vertical shift

Step-by-step explanation:

y=a(x-h)^2+k

This gives the parabola in vertex form

(h,k) is the vertex where h is the x coordinate and k is the y coordinate

k is the vertical shift

4 0
2 years ago
What values of c and d make the equation true? Assume x>0 and 20.
Grace [21]

Answer:

c=1 and c=3

Step-by-step explanation:

If x>0 and y>0, then

\sqrt{\dfrac{50x^6y^3}{9x^8}}=\sqrt{\dfrac{25\cdot 2y^2\cdot y}{9x^2}}=\dfrac{5y\sqrt{2y}}{3x}.

9x

8

50x

6

y

3

=

9x

2

25⋅2y

2

⋅y

=

3x

5y

2y

.

If

\dfrac{5y\sqrt{2y}}{3x}

3x

5y

2y

is equal to

\dfrac{5y^c\sqrt{2y}}{dx},

dx

5y

c

2y

,

then

\begin{gathered}y=y^c\Rightarrow c=1,\\ \\3x=dx\Rightarrow d=3.\end{gathered}

y=y

c

⇒c=1,

3x=dx⇒d=3.

5 0
1 year ago
I need the answer immediately!!!!!!!!
sergiy2304 [10]

Answer:y=-5x-2

Step-by-step explanation:

This will have a negative slope since the line goes from left to right. Use rise over run to find the slope of -5 and look at the y axis where it intersects to get -2

Have a great day!

8 0
1 year ago
Find the number of real number solutions for the equation. x2 + 5x + 7 = 0 0 2 1 cannot be determined
Marina CMI [18]

Answer:

0 solution

Step-by-step explanation:

Given

x^2 + 5x+ 7 = 0

Required

Find number of solutions;

The number of solutions can be determined via the value of determinants, D;

Such that

D = {b^2} - {4ac}

By comparing the general form of equation;

ax^2 +bc x + c = 0

with x^2 + 5x+ 7 = 0

This gives

a = 1\\b = 5\\c = 7

So;

D = {b^2} - {4ac} becomes

D = {5^2} - {4*1*7}

D = {25} - {28}

D = -3

The calculated value of D is less than 0;

This implies that x^2 + 5x+ 7 = 0 has no real solution

4 0
2 years ago
Name:<br> Date:<br> TRIGONOMETRIC IDENTITIES - DAY #1<br> ALGEBRA 2 WITH TRIGONOMETRY - HOMEWORK
Viefleur [7K]

Answer:

4567,4678..............

6 0
2 years ago
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