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4 years ago

5

Arthur made the Scatterplot below of the temperature outside his house over the course of nine days at the begging of winter if

this trend continues what would be most likely temperature outside Arthur’s house on day 10?

1 answer:

Oksi-84 [34.3K]4 years ago

7 0

20 degrees. The pics a little blurry, but it should be that

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Given the following diagram, find the required measure.

Zielflug [23.3K]

Answer:

∠ 5 = 40°

Step-by-step explanation:

∠ 1 and ∠ 2 are adjacent angles and supplementary, thus

∠ 2 = 180° - ∠ 1 = 180° - 140° = 40°

∠ 5 and ∠ 2 are alternate angles and congruent , thus

∠ 5 = 40°

3 0

3 years ago

What part of 3 1/2 is 1/2?

Greeley [361]

Answer:

the 1/2 part of it is 1/2

Step-by-step explanation:

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3 years ago

A motorist traveled 311 miles on 12 gallons of gas. To the nearest tenth, how many miles can the motorist travel on one gallon o

Alina [70]

D. 311 divided by 12 = 25.91
The nearest tenth would be 25.9

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3 years ago

Read 2 more answers

Noah says 4/9 is equivalent to 20/45. Check his work by completing the table of equivalent ratios.

g100num [7]

Noah is correct!!!! 20/45 simplified is 4/9. hope this helps!

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3 years ago

Read 2 more answers

Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)

Elis [28]

Answer:

Distance between point $(3,4)$ and midpoint of line joining $(8,10)$ and $(4,6)$ = $5$ units.

Step-by-step explanation:

Given:

Points:

$A(3,4)\\B(8,10)\\C(4,6)$

To find distance from point A to midpoint of BC.

Midpoint M of BC:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\$

$M=(\frac{8+4}{2},\frac{10+6}{2})\\$ [Plugging in points $B(8,10)\ and\ C(4,6)$ ]

$M=(\frac{12}{2},\frac{16}{2})\\$

$M=(6,8)\\$

Distance between A and M:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

$D=\sqrt{(6-3)^2+(8-4)^2} \\$ [Plugging in points $A(3,4)\ and\ M(6,8)$ ]

$D=\sqrt{(3)^2+(4)^2} \\$

$D=\sqrt{9+16} \\$

$D=\sqrt{25} \\$

$D=\pm5$

Since distance is always positive ∴ $D= 5$ units

4 0

3 years ago