Answer: The flagpole is about 22.3 feet tall.
This is roughly the size of a two story building, assuming each floor is 10 feet or so.
Since this height is under 25 ft, this flagpole is in compliance with the regulation.
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Work Shown:
The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.
The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.
Use the tangent rule to connect the opposite and adjacent sides.
Solve for x.
tan(angle) = opposite/adjacent
tan(25) = (x-5.5)/36
36*tan(25) = x-5.5
x-5.5 = 36*tan(25)
x = 36*tan(25)+5.5
x = 22.28707569358
x = 22.3 ft is the approximate height of the flagpole
Make sure your calculator is in degree mode.
The height is not over 25 ft, so this flagpole meets the requirements.
Solving a system of equations we can see:
- Sutopa has $73.20
- Maneet has $97.60
- Kim has $115.60
<h3>
How much money each of them has?</h3>
First, let's define the variables:
- S = money that Sutopa has.
- M = money that Maneet has.
- K = money that Kim has.
We can write the system of equations:
S = (3/4)*M
M = K - $18
S + M + K = $286.40
First, we can rewrite the second equation to get:
K = M + $18
Now we can replace the first and second equations into the third one:
(3/4)*M + M + (M + $18) = $286.40
Now we can solve this for M:
M*(1 + 1 + 3/4) = $286.40 - $18
M = $268.40*(4/11) = $97.60
Now we can find the other two values:
K = M + $18 = $97.60 + $18 = $115.60
S = (3/4)*M = (3/4)*$97.60 = $73.20
If you want to learn more about systems of equations:
brainly.com/question/13729904
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9514 1404 393
Answer:
dy/dx = y/(2x)
Step-by-step explanation:
The product formula can be used, along with the power rule.
d(uv) = du·v +u·dv
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d(y^2/x) = d(18)
2y·dy/x -y^2/x^2·dx = 0
2x·dy -y·dx = 0 . . . . . . . . multiply by x^2/y
dy/dx = y/(2x) . . . . . . . . add y·dx, divide by 2x·dx
Answer:
The answer is c
Step-by-step explanation:
