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Sliva [168]
3 years ago
10

I need help with these 2 please

Mathematics
1 answer:
Hoochie [10]3 years ago
5 0

Answer:

(-2 , 5) (2 , 3)

m = y2 - y1 / x2 - x1

= 3 - 5 / 2 + 2

- 2 / 4 = - 1/2

- 1/2 = y - 3 / x - 2

cross multiply and u get

y = -0.5x + 4

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Select all pairs of numbers that have a least common multiple of 30.
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5 and 6  and 3 and 10, the pairs of numbers that have a least common multiple of 30.

<u>Step-by-step explanation:</u>

Case 1: LCM (3, 6)

Prime factorization of 3:  1 \times 3

Prime factorization of 6:  2 \times 3

Using all prime numbers found as often as each occurs most often we take

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Case 2: LCM (5, 6)

Prime factorization of 5:  1 \times 5

Prime factorization of 6:  2 \times 3

Using all prime numbers found as often as each occurs most often we take

                     5 \times 2 \times 3=30

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Case 3: LCM (3, 10)

Prime factorization of 3:  1 \times 3

Prime factorization of 10:  2 \times 5

Using all prime numbers found as often as each occurs most often we take

                    5 \times 2 \times 3=30

Therefore LCM (3, 10) = 30

Case 4: LCM (5, 10)

Prime factorization of 5:  1 \times 5

Prime factorization of 10: 2 \times 5

Using all prime numbers found as often as each occurs most often we take

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