1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
asambeis [7]
3 years ago
11

Which of the following are integer solutions to the inequality below? −2≤×<3

Mathematics
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

-2, - 1, 0, 1, 2

Step-by-step explanation:

The greater than or equal to sign (≤) demonstrates that the unknown is equal to -2 and greater, but is less than 3, so the largest integer solution is 2, not 3

You might be interested in
Since school is over here ya go 100 points
harkovskaia [24]

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Lee scored 15 goals out of 35 attempts. What fraction of her attempts were successful?
V125BC [204]
15/35 of her attempts were successful.
8 0
3 years ago
Read 2 more answers
Evaluate the expression 5^3 ÷ (13 − 8) × 2. Numerical Answers Expected!
RoseWind [281]

Answer:50

Step-by-step explanation: simplify

4 0
3 years ago
Read 2 more answers
2/7m-1/7=3/14 solve step by step
yulyashka [42]

Solution for \frac{2}{7}m - \frac{1}{7} = \frac{3}{14} \ is \ m = \frac{5}{4} \ or \ m = 1\frac{1}{4} \ or \ m = 1.25

<h3>Further explanation</h3>

It is a case about one variable linear quations and we have to solve the equation to get the variable m. There are two ways to solve it!

Our main plan is to isolate the variable m alone at the end of the process on one side of the equation until the variable will be equal to the value on the opposite side.

<u>First way</u>

\frac{2}{7}m - \frac{1}{7} = \frac{3}{14}

Let us add \frac{1}{7} to both sides

\frac{2}{7}m - \frac{1}{7} + \frac{1}{7} = \frac{3}{14} + \frac{1}{7}

\frac{2}{7}m = \frac{3}{14} + \frac{1}{7}

On the right side for the addition operation, we equate the common denominator by multiplying \ \frac{1}{7} \ by \ \frac{2}{2}

\frac{2}{7}m = \frac{3}{14} + \frac{2}{14}

Then we combine terms to get

\frac{2}{7}m = \frac{5}{14}

Divide by the coefficient of m, or in other words, multiply both sides by \frac{7}{2}

\frac{2}{7}m \times \frac{7}{2} = \frac{5}{14} \times \frac{7}{2}

Finally, the solution is obtained as follows

m = \frac{35}{28}

Simplify fractions, both the numerator and denominator are divided equally by 7.

\boxed{ \ m = \frac{5}{4} \ }

Convert into mixed fractions, we get:

\boxed{ \ m = 1 \frac{1}{4} \ }

In decimal form, we get

m = 1 \frac{25}{100} \rightarrow \boxed{ \ m = 1.25 \ }

<u>Second way (a quick way)</u>

\frac{2}{7}m - \frac{1}{7} = \frac{3}{14}

Because the denominators 7 and 14 have LCM = 14, both sides are multiplied by 14 (LCM is the Least Common Multiple)

14 \times \big( \frac{2}{7}m - \frac{1}{7} \big) = 14\times \big( \frac{3}{14} \big)

We use the distributive property of multiplication on the left side

\frac{28}{7}m - \frac{14}{7} = \frac{42}{14}

or it can also directly lead to

4m - 2 = 3

Add 2 to both sides, we get

4m = 5

Divide by the coefficient of m, or in other words, both sides are divided by 4

\boxed{ \ m = \frac{5}{4} \ }

Or, \boxed{ \ m = 1 \frac{1}{4} \ }

Or, m = 1 \frac{25}{100} \rightarrow \boxed{ \ m = 1.25 \ }

Wanna check the solution into the equation?

\big( \frac{2}{7} \times \frac{5}{4} \big) - \frac{1}{7} = \frac{3}{14}

\frac{10}{28} - \frac{1}{7} = \frac{3}{14}

\frac{5}{14} - \frac{2}{14} = \frac{3}{14}

\frac{3}{14} = \frac{3}{14}

Both sides show the same value, so the solution is correct.

Note:

Remember, how to manipulate both sides of the equation with the algebraic properties of equality such as:

  • adding,
  • subtracting,
  • multiplying, and/or
  • dividing both sides of the equation with the same number.

In the form of fractions, the steps that must be considered are

  • equate the denominator,
  • simplify fractions, and
  • for the final answer, convert fractions to mixed fractions or decimal forms

All these processes can occur repeatedly until the isolated variables are obtained on one side of the equation.

<h3>Learn more</h3>
  1. A word problem that forms a single variable linear equation brainly.com/question/1566971
  2. Learn more about the single variable linear equation that has no solution, has one solution, and has infinitely many solutions brainly.com/question/2595790  
  3. Questioning the stages of solving a word problem about one variable linear equations brainly.com/question/2038876
<h3>Answer details  </h3>

Grade : Middle School

Subject : Mathematics

Chapter : Linear Equation in One Variable

Keywords : solve, solution, variable, coefficient, 2/7m - 1/7 = 3/14,  5/4, 1 1/4, 1.125, algebraic properties of equality, one, linear equation, isolated, manipulate, operations, add, subtract, multiply, divide, fraction, equate, denominator, numerator, both sides, decimal

4 0
3 years ago
Read 2 more answers
What is the question is 100x 200 is
Vikentia [17]

Answer:

20,000 because I used my head

6 0
2 years ago
Other questions:
  • What is the vertex of the function f (x) = x^2 + 16x?
    11·1 answer
  • If cos f° = four ninths and the measure of segment XW is 16 units, what is the measure of segment XY?
    7·1 answer
  • √√Math Help Please √√<br> I need it today
    5·2 answers
  • Solve the system of equations<br> y=-3/2x+9 <br> 2x+2y=16
    15·1 answer
  • The probability of randomly selecting two oranges from a bowl of 5 oranges and 4 tangerines if the first selection is replaced
    12·1 answer
  • 44735758 x 46639756-435333 divided by 48883 = what pls help will give brainleist
    14·2 answers
  • Can someone pl help me
    6·1 answer
  • The simple interest on $2,000 for 2 years is $320. What is the interest rate?
    13·1 answer
  • 5. Find the area of the composite figure.
    15·1 answer
  • annie has some sweets. teddy gives her some sweets and she now has 50% more . rosie gives her some sweets and she now has an ext
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!