What is the area of ΔABC? Round to the nearest tenth of a square unit.
2 answers:
<span><u><em>Answer:</em></u>
8.4 square units
<u><em>Explanation:</em></u>
<u>The area of the triangle can be calculated using two sides and an included angle as follows:</u>
area = 0.5 * 1st side * 2nd side * sin(angle included between them)
............> This is shown in the attached image
<u>In the given triangle, we have:</u>
the two sides 2*</span>√2<span> and 6 units
the angle included between them is 80</span>°<span>
Therefore, we can apply the above rule to get the area as follows:
area = 0.5 * 2</span>√2 <span>*6* sin(80</span>°<span>)
area = 8.35 which is approximately 8.4 square units
Hope this helps :)</span>
8.4 square units
<u><em>Explanation:</em></u>
<u>The area of the triangle can be calculated using two sides and an included angle as follows:</u>
area = 0.5 * 1st side * 2nd side * sin(angle included between them)
............> This is shown in the attached image
<u>In the given triangle, we have:</u>
the two sides 2*</span>√2<span> and 6 units
the angle included between them is 80</span>°<span>
Therefore, we can apply the above rule to get the area as follows:
area = 0.5 * 2</span>√2 <span>*6* sin(80</span>°<span>)
area = 8.35 which is approximately 8.4 square units
Hope this helps :)</span>
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Answer:
Step-by-step explanation:
Given:
Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).
So, the 'x' value is 3 and 'y' value id -4.
Using Pythagoras Theorem, we find the hypotenuse.
Hypotenuse =
Now, using the sine ratio for the angle, we have
Therefore, the value of is
.
The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,
