The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
Read more about binomial expansion at
brainly.com/question/13602562
#SPJ1
Answer:
If I’m not wrong I think it’s the first one
Step-by-step explanation:
Step-by-step explanation:
x=20
y=100
solution in image
The answer c, because they got 9 out of 15 flips being heads. This probability is 0.6. The other answers are not accurate.
<span>If 3x-1=11, then 2x=?
</span><span>
2x + x - 1 = 11
2x = -x +12</span>
