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Gwar [14]
3 years ago
12

5x-2=3x+8 must find what X is equal to

Mathematics
2 answers:
serious [3.7K]3 years ago
6 0
I had homework on this today lol

First, add 2 to both sides. It would then be 5x = 3x + 10. Then subtract 3x from both sides and you would end up with 2x = 10. Divide 2x by 2 and the 10 by 2. The answer is x = 5.
Blababa [14]3 years ago
4 0
Subtract 3x from both sides
2x-2=8

Add 2 to both sides
2x=10

Divide both sides by 2
x=5

Final answer: x=5
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Answer:

62.83 cm is the length of the ribbon needed

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What is 3 1/4 + 2 1/8<br><br> A) 5 1/6<br> B) 5 3/8<br> C) 5 1/2<br> D) 5 3/4
love history [14]

Answer:

The correct answer would be B.

Step-by-step explanation:

3 1/4 + 2 1/8

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Hope this helps!

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5 0
3 years ago
The flow of water from a water faucet can fill a 3 gallon container in 15 seconds. Give the ratio of gallons to seconds as a rat
kkurt [141]

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7 0
3 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


6 0
4 years ago
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