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3 years ago

What is the Area of the compound shape below? *

Mathematics

1 answer:

Ray Of Light [21]3 years ago

7 0

Answer:

22m²

Step-by-step explanation:

2 wide, 9 height is 18 for the rectangle figure. We see that the rectangle figure has a width of 2 while the entire width is 4. So 4-2 means the width of the right triangle that's split off is 2.

We see the rectangle height is 5, and total figure is 9, so 9-5 = height of 4 for the triangle.

4x2 x 1/2(since its a triangle) = 4

4+18 = 22

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The height of a box can be found by dividing its volume by the area of its base,bottom.What is the height of a box that has a vo

SOVA2 [1]

Answer:

6.2 cm

Step-by-step explanation:

$\dfrac{26.35\,\text{cm}^{3}}{4.25\,\text{cm}^{2}}=6.2\,\text{cm}$

The height of the box is 6.2 cm.

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4 years ago

Question 6 of 10

liraira [26]

Answer:

It's A

Step-by-step explanation:

I've already done this!

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3 years ago

Read 2 more answers

Select the correct answer.

Maru [420]

The true statement about these graph is that: B. the graph of the original function (y = 8/5x + 4) is perpendicular to the graph of the new function (y =- 5/8x + 8).

<h3>What is a graph?</h3>

A graph can be defined as a type of chart that's commonly used to for the graphical representation of data on both the horizontal and vertical lines of a Cartesian coordinate, which are typically known as the x-axis and y-axis respectively.

<h3>How to interpret the graph?</h3>

Mathematically, the standard form of the equation of a straight line on a graph is given by;

y = mx + c

<u>Where:</u>

x and y are the points.

m is the slope.

c is the intercept.

<h3>The condition for perpendicularity.</h3>

In Mathematics, the condition for perpendicularity of two (2) lines is as follows:

m₁ × m₂ = -1

8/5 × (-5/8) = -1

Based on the graph (see attachment) of the original function and new function, we can infer and logically deduce that the true statement about their graph is that the graph of the original function (y = 8/5x + 4) is perpendicular to the graph of the new function (y =- 5/8x + 8).

Read more on perpendicularity here: brainly.com/question/1202004

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Complete Question:

Suppose the following function is graphed. y = 8/5x + 4 On the same grid, a new function is graphed. The new function is represented by the following equation. y =- 5/8x + 8. Which of the following statements about these graphs is true?

A. The graphs intersect at (0,8).

B. The graph of the original function is perpendicular to the graph of the new function.

C. The graph of the original function is parallel to the graph of the new function.

D. The graphs intersect at (0,4).

3 0

2 years ago

The graph of which function has an axis of symmetry at x =-1/4 ?

Phoenix [80]

we know that

The equation of the vertical parabola in vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex

The axis of symmetry is equal to the x-coordinate of the vertex

$x=h$ ------> axis of symmetry of a vertical parabola

we will determine in each case the axis of symmetry to determine the solution

<u>case A)</u> $f(x)=2x^{2}+x-1$

<u>Convert to vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+1=2x^{2}+x$

Factor the leading coefficient

$f(x)+1=2(x^{2}+0.5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+1+0.125=2(x^{2}+0.5x+0.0625)$

$f(x)+1.125=2(x^{2}+0.5x+0.0625)$

Rewrite as perfect squares

$f(x)+1.125=2(x+0.25)^{2}$

$f(x)=2(x+0.25)^{2}-1.125$

the vertex is the point $(-0.25,-1.125)$

the axis of symmetry is

$x=-0.25=-\frac{1}{4}$

therefore

the function $f(x)=2x^{2}+x-1$ has an axis of symmetry at $x=-\frac{1}{4}$

<u>case B)</u> $f(x)=2x^{2}-x+1$

<u>Convert to vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-1=2x^{2}-x$

Factor the leading coefficient

$f(x)-1=2(x^{2}-0.5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-1+0.125=2(x^{2}-0.5x+0.0625)$

$f(x)-0.875=2(x^{2}-0.5x+0.0625)$

Rewrite as perfect squares

$f(x)-0.875=2(x-0.25)^{2}$

$f(x)=2(x-0.25)^{2}+0.875$

the vertex is the point $(0.25,0.875)$

the axis of symmetry is

$x=0.25=\frac{1}{4}$

therefore

the function $f(x)=2x^{2}-x+1$ does not have a symmetry axis in $x=-\frac{1}{4}$

<u>case C)</u> $f(x)=x^{2}+2x-1$

<u>Convert to vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+1=x^{2}+2x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+1+1=x^{2}+2x+1$

$f(x)+2=x^{2}+2x+1$

Rewrite as perfect squares

$f(x)+2=(x+1)^{2}$

$f(x)=(x+1)^{2}-2$

the vertex is the point $(-1,-2)$

the axis of symmetry is

$x=-1$

therefore

the function $f(x)=x^{2}+2x-1$ does not have a symmetry axis in $x=-\frac{1}{4}$

<u>case D)</u> $f(x)=x^{2}-2x+1$

<u>Convert to vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-1=x^{2}-2x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-1+1=x^{2}-2x+1$

$f(x)=x^{2}-2x+1$

Rewrite as perfect squares

$f(x)=(x-1)^{2}$

the vertex is the point $(1,0)$

the axis of symmetry is

$x=1$

therefore

the function $f(x)=x^{2}-2x+1$ does not have a symmetry axis in $x=-\frac{1}{4}$

<u>the answer is</u>

$f(x)=2x^{2}+x-1$

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4 years ago

Read 2 more answers

Whats is the measure of x

Sophie [7]

What exactly is the question? I dont see any

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3 years ago