Question

Eva wants to make two pieces of pottery. She needs 3/5 pound of clay for one piece and 7/10 pound of clay for the other piece. She has 3 bags of clay that weigh 4/5 pounds each. How many bags of clay will Eva need to make both pieces of pottery? How many pounds of clay will she have left?

Answer 1

we know that

Eva needs $\frac{3}{5}$ pound of clay for one piece and $\frac{7}{10}$ pound of clay for the other piece

Step 1

Find the total pound of clay for the two pieces

$\frac{3}{5} +\frac{7}{10} =\frac{(2*3+7)}{10} \\ \\ =\frac{13}{10} pounds$

Eva has $3$ bags of clay that weigh $\frac{4}{5}$ pounds each.

Step 2

Find the total weigh of the $3$ bags of clay

$3*\frac{4}{5} =\frac{12}{5} pounds$

Part a ) How many bags of clay will Eva need to make both pieces of pottery?

by using proportion

$\frac{1}{\frac{4}{5}} =\frac{x}{\frac{13}{10}} \\ \\ \frac{13}{10} =\frac{4}{5} x\\ \\ x=\frac{5*13}{4*10} \\ \\ x=\frac{65}{40} \\ \\ x=1.625bags$

therefore

the answer Part a)

she needs $2$ bags

Part b) How many pounds of clay will she have left?

Calculate the total weigh of the $3$ bags of clay minus the total pound of clay for the two pieces

so

$\frac{12}{5} -\frac{13}{10} =\frac{(2*12-13)}{10} \\ \\ =\frac{(24-13)}{10} \\ \\ =\frac{11}{10} \\ \\ =1\frac{1}{10} pounds$

therefore

the answer Part b) is

$1\frac{1}{10} pounds$