Answer:
I don’t know how to help you with that because I don’t have your math journal. And stander form of what exactly?
W^(2)-6w-16
I hope this helped c;..............................
Answer:
a) m∠FGH= 28°
b) m∠HGI = 28°
c) m ∠FGI = 56°
Step-by-step explanation:
GH bisects ∠FGI. So, ∠FGH = ∠HGI
5x - 2 = 6x -8
5x - 6x = 2 - 8
-x = - 6
x = 6
a) m∠FGH = 5x - 2 = 5 * 6 - 2 = 30 - 2 = 28°
b) m∠HGI = 6x - 8 = 6 * 6 - 8 = 36 - 8 = 28°
c) m ∠FGI = m∠FGH + m∠HGI = 28° +28° = 56°
Answer:
Step 2
Step-by-step explanation:
I'm not that sure but I think that its right
Hello,
Answer (1-√5,0) , (1+√5,0)
Indeed,
S=(1,20)
==> y=k*(x-1)²+20
(0,16) is a point of the parabola
==>16=k*(0-1)²+20==>k=-4
Parabola: y=-4(x-1)²+20
if y=0 then -4(x-1)²+20=0==> 4(x-1)²=20=> (x-1)²=5 ==> x=1+√5 or x=1-√5
