Using the simple interest formula, the interest paid for the loan of $7890 at 11.5% for a term of 5 years will be:
S.I=(PRT)/100
S.I=(7890×11.5×5)/100
=$4536.75
Answer:
Option C. Stem Leaves 6 7 7 2 5 8 5 7 9 9 9 0 9 10 0
Option D.
Step-by-step explanation:
The data values are 67, 72, 85, 75, 89, 89, 87, 90, 99 and 100.
Arranging the data values in ascending order
67, 72, 75, 85, 87, 89, 89, 90, 99, 100
The stem and lead plot can be shown under and stem is denoted as "S" whereas leaves are denoted as "L".
S L
6 7
7 2 5
8 5 7 9 9
9 0 9
10 0
The longer row of stem indicates the higher frequencies and so the length of rows are similar to the heights of bars in histogram.
Answer:
0
Step-by-step explanation:
(-7 + 3) - (2 - 6)
PEMDAS
Parentheses first
(-4) - (-4)
Subtracting a negative is adding
-4 +4
0
Answer:
Null hypothesis:
Alternative hypothesis:
![p_v = 2*P(|z|>z_{calc})](https://tex.z-dn.net/?f=%20p_v%20%3D%202%2AP%28%7Cz%7C%3Ez_%7Bcalc%7D%29)
And the best answer for this case is:
C. p-value
Step-by-step explanation:
Data given and notation
n represent the random sample taken
estimated proportion of interest
is the value that we want to test
represent the significance level
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the true proportion i 0.72 or no.:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion
is significantly different from a hypothesized value
.
For this case the only probability that can be calculated from the statistic calculated is the p value given by:
![p_v = 2*P(|z|>z_{calc})](https://tex.z-dn.net/?f=%20p_v%20%3D%202%2AP%28%7Cz%7C%3Ez_%7Bcalc%7D%29)
And the best answer for this case is:
C. p-value