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2 years ago

13

Explain why sides that are next to each other in a net have the same side lengths?

1 answer:

Monica [59]2 years ago

5 0

Answer:

Note: Two sides are congruent if they have the same length and angles are congruent if they have the same measure.

Step-by-step explanation:

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Find the solutions of the quadratic equation 3x^2-2x+7=0<br> PLEASE ANSWER CORRECTLY!!

BigorU [14]

Answer:

Step-by-step explanation:

8 0

2 years ago

strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, formulas for the candle are described below:

$V = \pi\cdot r^{2}\cdot h$ (1)

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$ (2)

Where:

$r$ - Radius, in centimeters.

$h$ - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

$h = \frac{V}{\pi\cdot r^{2}}$

By substitution in (2) we get the following formula:

$A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)$

$A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}$

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

$4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0$

$4\pi\cdot r^{3} - 2\cdot V = 0$

$2\pi\cdot r^{3} = V$

$r = \sqrt[3]{\frac{V}{2\pi} }$

There is just one result, since volume is a positive variable.

Second Derivative Test

$A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}$

If $\left(r = \sqrt[3]{\frac{V}{2\pi}}\right)$ :

$A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }$

$A_{s} = 12\pi$ (which means that the critical value leads to a minimum)

If we know that $V = 3217\,cm^{3}$ , then the dimensions for the minimum amount of plastic are:

$r = \sqrt[3]{\frac{V}{2\pi} }$

$r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}$

$r = 8\,cm$

$h = \frac{V}{\pi\cdot r^{2}}$

$h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}$

$h = 16\,cm$

And the amount of plastic needed to cover the outside of the candle for packaging is:

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$

$A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)$

$A_{s} \approx 1206.372\,cm^{2}$

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

3 0

2 years ago

The number of students taking classes at RSM Branch A is 1

juin [17]

Answer:

B = 1320

$A= \dfrac54B$

Step-by-step explanation:

Let A = number of students at Branch A

Let B = number of students at Branch B

If the number of students taking classes at Branch A is 1/4 more than Branch B, then:

$A=1 \dfrac14B$

$\implies A= \dfrac54B$

If Branch A has 1,650 students, then substitute A = 1650 and solve for B:

$\implies 1650= \dfrac54B$

$\implies 1650 \times 4= 5B$

$\implies 6600 =5B$

$\implies B=\dfrac{6600}{5}$

$\implies B=1320$

6 0

2 years ago

Read 2 more answers

Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?

disa [49]

Just see my atachment.

6 0

3 years ago

Read 2 more answers

-3-2(2x-3) simplified

ddd [48]

First Distribute, then subtract and you’ll get -4x+3

6 0

2 years ago