All categories

3 years ago

Explain why sides that are next to each other in a net have the same side lengths?

Mathematics

1 answer:

Monica [59]3 years ago

5 0

Answer:

Note: Two sides are congruent if they have the same length and angles are congruent if they have the same measure.

Step-by-step explanation:

You might be interested in

Please help with math homework problem! thank you!!

Elan Coil [88]

The answer is 47L my man

8 0

3 years ago

Read 2 more answers

Calculate the slope of the line that passes through the points<br><br> (1,3) (3,negative2)

Andreyy89

Slope is rise over run or (y₁-y₂)/(x₁-x₂)

(x,y)
(1,3)
(3,-2)

(3-(-2))/(1-3)=(3+2)/(1-3)=5/-2

slope is -5/2

4 0

3 years ago

Read 2 more answers

Help me please please

Serggg [28]

Answer:

-2,10

Step-by-step explanation:

fjcvbd,f.jf

5 0

3 years ago

Factorizar o descomponer en de FACTORES

Charra [1.4K]

Not sure if you’re speaking Spanish or not but yes

5 0

2 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

2 years ago