Can someone help me with this problem?
1 answer:
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9514 1404 393
Answer:
D. (0, 6)
Step-by-step explanation:
The origin is where the axes cross. The coordinates of that point are (0, 0). The distance of a point (x2, y2) from point (x1, y1) is given by the distance formula ...
d = √((x2 -x1)² +(y2 -y1)²)
When (x1, y1) = (0, 0), this reduces to ...
d = √(x² +y²)
We want to find (x, y) such that d=6. This can be a little easier if we square both sides of the equation to eliminate the radical.
x² +y² = 6² = 36
This is the equation of a circle of radius 6 centered at the origin: all points that are distance 6 from the origin. So, any point on the circle will be at a distance of 6 from the origin.
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The sum of squares in each case is ...
A. 3² +0² = 9 . . . inside the circle
B. 4² +2² = 20 . . . inside the circle
C. 5² +3² = 34 . . . inside the circle
D. 0² +6² = 36 . . . on the circle at a distance of 6 from the origin
E. 4² +4² = 32 . . . inside the circle
F. 1² +5² = 26 . . . inside the circle
Answer:
4.472135955
Step-by-step explanation:
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