As per the reference document attached thereby along with the question statement, if (∠SOX = 160°), [∠1 = (x + 14)], and [∠2 = (3x – 10)], then the measure of ∠2 in degrees will be 113°
As per the reference document attached thereby along with the question statement, (∠SOX = 160°), and it's constituent angles
[∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)],
And we are required to determine the measure of ∠2.
Since, [(∠SOW + ∠WOX) = ∠SOX],
Therefore, [{(x + 14) + (3x – 10)} = 160°]
Or, [{(x + 3x) + (14 - 10)} = 160°]
Or, [(4x - 4) = 160°]
Or, [4x = (160 + 4)°]
Or, (4x = 164°)
Or, [x = (164/4)°]
Or, (x = 41°)
Or, [(3x – 10) = {(3 * 41) - 10}°]
Or, [∠2 = (123 - 10)°]
Or, (∠2 = 113°)
That is, if (∠SOX = 160°), and it's constituent angles (∠1) and (∠2) measure as [∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)], then the measure of ∠2 in degrees will be 113°
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