3x + 2y + 6z = 5??
then
distance = |3(1) + 2(-2) + 6(4) - 5| / √(3^2 + 2^2 + 6^2)
the plane is ax + by + cz - d = 0 while the point is (x1, y1, z1)
Answer:
x = - 8/23
y = 40/23
Step-by-step explanation:
-5x- y = 0
and
-8x+3y = 8
The first step to solve this would be to get what one of the two variables equal. The easiest in this case is y from the first equation.
-5x-y = 0
-y = 5x
y = - 5x
Now you can take this y value and plug it into the section equation.
-8x + 3(-5x) = 8
-8x - 15x = 8
-23x = 8
x = - (8/23)
Once you get the x value you can plug it back into equation one to get y's value
-5*-(8/23) - y = 0
40/23 - y = 0
y = 40/23
9 combinations hope it helps
Answer:
2731
Step-by-step explanation:
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