It mean benchmarks in out side of math
a criterion by which to measure something; standard; reference point
Answer:
Step-by-step explanation:
There is no solution

<u>Step-by-step explanation:</u>
We have ,
,
We know that ![sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }](https://tex.z-dn.net/?f=sin%5Calpha%20%20%3D%20%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%20%3D%20%5Cfrac%7BPerpendicular%7D%7B%5Csqrt%5B2%5D%7B%28Perpendicualr%29%5E%7B2%7D%20%2B%20%28Base%29%5E%7B2%7D%29%7D%20%7D)
Substituting values of P & B , 
Now , 
⇒
×
×2
⇒ 
⇒
⇒
⇒
Answer:
<em>Domain:</em> -3 < x <2
<em>Range:</em> -4 < y < 5
<em>Is the graph a function?</em> No the graph isn't not, since the graph fails the <em>vertical line test</em>
Answer:
-7/2
Step-by-step explanation: