Question

Tess created a Pythagorean triple of (24, 32, 40) by multiplying the known Pythagorean triple 3, 4, and 5 by 8. Is Tess correct? Can a Pythagorean triple be created using multiples of a known Pythagorean triple.
Yes, as long as each number in the Pythagorean triple is multiplied by the same whole number.
Yes, as long as each number in the Pythagorean triple is multiplied by a different whole number.
No, Pythagorean triples only exist with small numbers.
No, multiplying a known Pythagorean triple by a whole number will not create a Pythagorean triple.

Answer 1

Answer:

Yes, as long as each number in the Pythagorean Triple is multiplied by the same whole number.

General Formulas and Concepts:

Pre-Algebra

• Equality Property

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

• a is a leg
• b is another leg
• c is the hypotenuse

Step-by-step explanation:

In order for it to remain a Pythagorean triple, we must follow the equality rules. To make it the exact same expression, all parts of an equation must be multiplied or divided by the same number. If this is done, then it would also remain a Pythagorean triple, and hence we arrive at our answer.

Answer 2

Answer:

Hello,

Answer A

Yes, as long as each number in the Pythagorean triple is multiplied by the same whole number.

Step-by-step explanation:

(a,b,c) is a Pythagorien triple  : c²=a²+b²

and k is a naturel.

$(ka)^2+(kb)^2\\\\=k^2*a^2+k^2*b^2\\\\=k^2(a^2+b^2)\\\\=k^2c^2\\\\=(kc)^2$