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2 years ago

Find equation of the line passing through(0,-3),which has a gradient of 2

Mathematics

1 answer:

WINSTONCH [101]2 years ago

7 0

Answer:

y = 2x - 3

Step-by-step explanation:

y - - 3 = 2(x-0)

y + 3 = 2x

y = 2x -3

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|2x−10|=−3x solve for x

lianna [129]

Answer:

X = 0

Step-by-step explanation:

BECAUSE ITS AN ABSOLUTE VALUE FUNCTION

6 0

2 years ago

When Akiko measured a rose, its height was 5.8 in. After 10 weeks, the height was 1 1/3 times the original height. What was the

kramer

The solution is in the attachment

8 0

2 years ago

On a certain day the exchange rate was 60 u.s dollars 50 euro. How many US dollars were 70 euro worth that day? Show that your a

gayaneshka [121]

This is what I got:

60/50 = X/70
70x60/59 = X
X = 84

8 0

2 years ago

Can someone PLEASE help me solve this equation ? due soon

RideAnS [48]

$\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}$

We know that : (a - b)(a + b) = a² - b²

$\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}$

We know that : 1 - sin²x = cos²x

$\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}$

$\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}$

$\implies \sf{3tanx + 7 = 2sec^2x}$

We know that : sec²x = 1 + tan²x

$\implies \sf{3tanx + 7 =2(1 + tan^2x)}$

$\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}$

$\implies \sf{2tan^2x - 3 tanx - 5 = 0}$

$\implies \sf{2tan^2x - 5tanx + 2tanx - 5 = 0}$

$\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}$

$\implies \sf{(tanx + 1)(2tanx - 5) = 0}$

$\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }$

8 0

2 years ago

How to graph 9x+5y=-45

lilavasa [31]

9x +5y= -45 put in standard form y= mx+b coefficient of x is the slope, b is the y intercpept 5y= -9x -45 y= -9/5 x -45 graphing will start at -45 on the y axis from that point go down 9 to the right 5 for the slope continue and graph minimum 2 points to draw the line hope this helps

8 0

2 years ago