<span>a³-b³=(a-b)(a²+ab+b²)
64x⁶ - 27
64 = 4³,
x⁶ = (x²)³
27 = 3³
</span>64x⁶ - 27 = 4³(x²)³ -3³ = (4x²)³ -3³. Now, we can use a formula where a=4x², b=3
(4x²)³ -3³ = (4x² -3)((4x²)² +4x²*3 + 3²) = (4x² -3)(16x⁴ +12x² + 9)
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Answer: </span>64x⁶ - 27= (4x² -3)(16x⁴ +12x² + 9) <span>
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There are 12 possible arrangements.
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- Considering that the blue cup has to be on one end, we consider the number of arrangements possible with the other 4 cups, then multiply by 2(considering the blue on each end).
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- Considering green and yellow before red and purple, there are
outcomes(G-Y-R-P, G-Y-P-R, Y-G-R-P and Y-G-P-R). - Another two possible outcomes are yellow-purple and green-red, or vice-versa, thus 4 + 2 = 6 outcomes.
- To account for the blue on the end, multiplying by 2.

- There are 12 possible arrangements.
A similar problem is given at brainly.com/question/24617788
1 cm because 1 cm * 1 cm * 1 cm = 1 cm
Answer: I would say rolling a number cube
Step-by-step explanation:
when flipping a coin you will have a 1/2 chance of landing on heads and then when spinning the spinner you would have a 3/4 chance since there is 3 numbers greater then 1 and then with the cube since it has 6 sides and your only getting 1 or two you would have a 2/6 chance.
Answer:
y = 5
Step-by-step explanation:
cross-multiply:
6y = 30
y = 5