Are you trying to distribute the b^4 or factor it?
b^4 [(2b^2) + b]
Distributed:
[2(b^6) + (b^5)]
Factored:
b^5 [2b + 1]
6(2)+3y=15
12+3y=15
-12 -12
3y=3
3y/3 3/3
y=1
6(5)+3y=15
30+3y=15
-30 -30
3y=-15
3y/3 -15/3
y= -5
9514 1404 393
Answer:
-130 °C
Step-by-step explanation:
The change is found by subtracting the start temperature from the finish temperature. It is ....
-60 °C - 70 °C = -130 °C
Answer:
7:6
Step-by-step explanation:
yan ng sagot dont forget to heart
Answer:
2(3x + 7)(2x - 1)
Step-by-step explanation:
You can see it a little easier if you take out a common factor of 2
2(6x^2 + 11x - 7)
The 6 leaves you with a lot of factors, the 7 does not. It only has 2 factors.
Let 6 factor into 2 and 3 and the 7 into 7 and 1
2(3x - 1 )(2x + 7)
Now remove the brackets.
2(6x^2 + 21x - 2x - 7) This obviously does not work but we'll combine like terms anyway.
2(6x^2 + 19x - 7)
So we'll try it again
2(3x + 7)(2x - 1)
2(6x^2 + 14x - 3x - 7) Looks like we have it.
2(6x^2 + 11x - 7)
So the right factors are
2(3x + 7)(2x - 1)
