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kap26 [50]
3 years ago
12

Working as a team, 8 mathletes can solve 20 problems in 10 minutes. At this same rate, how many mathletes are needed in order to

solve 30 problems in 5 minutes?
Mathematics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

12 mathletes is needed to solve 30 problems in 5 minutes

Step-by-step explanation:

8 athletes can solve 20 problems in 10 minutes

30-20=10

now we need 10 more problems to be solved so

20/2=10. 8/2=4 so we need more 4 mathletes to solve all the problems

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Mars2501 [29]

Answer:

y=x+20

Step-by-step explanation:

we have to find the slope

y2-y1/x2-x1

3-2/23-22

1/1

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y-22 = 1(x-2) + b

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5 0
4 years ago
your class sponsors a benefit concert and the tickets at $8 each.Jordan sells 12 tickets,Andy 16,Morgan 17,and Pat 13.Compute th
Irina18 [472]
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8 0
3 years ago
One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What
Roman55 [17]
The students ate 6 lbs of candies.
8 0
4 years ago
your gym membership cost $33 per month after an initial membership fee. you paid a total of $228 after 6 months. writer an equat
grin007 [14]

Answer:

what i did was multiply 33*6 and got 198 and then 228-198 to find out that the initial fee was 30 dollars. then multiply 33*9+30 to get a  9-month total cost of $327

Step-by-step explanation:

cost = $33 per month + fee  

1.  c(m) = 33m + f

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198 + f = 228

f = $30 membership fee  

c(m) = 33m + 30

 2.  at 9 months:  33(9) + 30 = $327

hopefully this helps :)

have a nice day !!

7 0
3 years ago
Find the product of these complex numbers (8+6i)(-5+7i)
spayn [35]

Answer:

Step-by-step explanation:

= -40 + 56i -30i +42i

= 68i - 40

3 0
2 years ago
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