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swat32
3 years ago
8

Here are the first five terms of a number sequence.

Mathematics
1 answer:
gogolik [260]3 years ago
3 0

Answer:

40 is surface the answer of I think about it but I will solve the sum and will give the ans

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3 years ago
Please help me with precalculus??<br>linear and angular speed
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13)

there are 2π radians in 1 revolution, and there are 60 seconds in 1 minute, so keeping that in mind, then,

\bf \cfrac{4\underline{\pi} }{5~\underline{s}}\cdot \cfrac{rev}{2\underline{\pi} }\cdot \cfrac{60~\underline{s}}{min}\implies \cfrac{4\cdot 60~rev}{5\cdot 2~min}\implies \cfrac{240~rev}{10~min}\implies 24\frac{rev}{min}

14)

 \bf \textit{linear velocity}\\\\&#10;v=rw\quad &#10;\begin{cases}&#10;r=radius\\&#10;w=angular~speed\\&#10;----------\\&#10;v=32\frac{m}{sec}\\&#10;w=100\frac{rev}{min}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\textit{let's convert \underline{w} to }\frac{radians}{sec}

\bf \cfrac{100~\underline{rev}}{\underline{min}}\cdot \cfrac{2\pi }{\underline{rev}}\cdot \cfrac{\underline{min}}{60~sec}\implies \cfrac{100\cdot 2\pi }{60~sec}\implies \cfrac{10\pi }{3~sec}\implies \cfrac{10\pi }{3}\frac{radians}{sec}\\\\&#10;-------------------------------\\\\&#10;v=rw\implies \cfrac{v}{w}=r\implies \cfrac{\frac{30~m}{sec}}{\frac{10\pi }{3~sec}}\implies r=\cfrac{30~m}{\underline{sec}}\cdot \cfrac{3~\underline{sec}}{10\pi }&#10;\\\\\\&#10;r=\cfrac{90}{10\pi }m

15)

what is the radians per seconds "w" in revolutions per minute?  just another conversion like in 13)

\bf \cfrac{\underline{\pi} }{3~\underline{sec}}\cdot \cfrac{rev}{2\underline{\pi }}\cdot \cfrac{60~\underline{sec}}{min}\implies \cfrac{60 ~rev}{3\cdot 2 ~min}\implies \cfrac{60 ~rev}{6 ~min}\implies 10\frac{rev}{min}
4 0
4 years ago
A line has a y-intercept of 7 and a slope of 2 . what is it’s equation in slope-intercept form
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Answer:

y=2x+7

Step-by-step explanation:

the slope is always the number before x. the y-intercept is the number added after x

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3 years ago
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Tre and Hector want to calculate the maximum possible throw at this field.
marissa [1.9K]

Answer:

d=455.38~units

Step-by-step explanation:

The coordinates of the dead center of the field, D\equiv (322,322)

Home base in a coordinate system is always the origin, O\equiv(0,0)

The center fielder threw the ball form the dead center to the home base, hence the distance of throw:

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

d=\sqrt{(322-0)^2+(322-0)^2}

d=455.38~units

4 0
3 years ago
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