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Svetradugi [14.3K]
3 years ago
13

Find the product. (y - 2bs^2) (y + 3bs^2) Enter the correct answer.

Mathematics
1 answer:
Vikentia [17]3 years ago
7 0

Answer:

y² + bs²y - 6b²s⁴

General Formulas and Concepts:

  • Expand by FOIL (First Outside Inside Last)
  • Exponent Power Rule: (b^m)^n=b^{mn}

Step-by-step explanation:

<u>Step 1: Define expression</u>

(y - 2bs²)(y + 3bs²)

<u>Step 2: FOIL</u>

  1. First:               y · y = y²
  2. Outside:         y · 3bs² = 3bs²y
  3. Inside:            -2bs² · y = -2bs²y
  4. Last:               -2bs² · 3bs² = -6b²s⁴

<u>Step 3: Simplify</u>

  1. Combine:                         y² + 3bs²y - 2bs²y - 6b²s⁴
  2. Combine like terms:        y² + bs²y - 6b²s⁴
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Step-by-step explanation:

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The table shows transactions in a checking account
Yuki888 [10]

Answer:

i) number of transactions for the month of January = 4

 number of transactions for the month of February = 4

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 number of transactions for the month of April = 4

ii) Mean of four months  = -495.7 /4 = -123.93

Step-by-step explanation:

i) number of transactions for the month of January = 4

 number of transactions for the month of February = 4

 number of transactions for the month of March = 4

 number of transactions for the month of April = 4

ii)     January              February              March            April

         -38.50                 250.00               -14.00           -86.80

         126.30                -135.20                 99.00          -570.00

         429.40                  35.50                -82.70           100.00

        -265.00                 -62.30                 -1.50           -280.10

Total  252.20                  88.20                 0.80            -836.9

Total of four months  = 252.2 + 88.20 + 0.80 - 836.9  =  -495.7

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Answer:

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Please do all problems with work on paper thank you​
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a. \frac{11}{12}

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Step-by-step explanation:

Step 1; First, we convert the given fractions into improper ones. To do this, we multiply the whole number with the denominator of the fraction and add with it the same fraction's numerator whereas the denominator remains unchanged. To convert the fraction

3\frac{1}{4} = (3 × 4) + 1 / 4 = \frac{13}{4},

2\frac{1}{3} = (2 × 3) + 1 / 3 = \frac{7}{3},

6\frac{1}{5} = (6 × 5) + 1 / 5 = \frac{31}{5},

4\frac{1}{4} = (4 × 4) + 1 / 4 = \frac{17}{4},

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Step 2; Now we subtract, using LCM to arrive at the answer

3\frac{1}{4} - 2\frac{1}{3} = \frac{13}{4} - \frac{7}{3} = \frac{39-28}{12} = \frac{11}{12},

6\frac{1}{5} - 4\frac{1}{4} = \frac{31}{5} - \frac{17}{4} = \frac{124-85}{20} = \frac{39}{20},

5\frac{2}{7} - 4\frac{1}{3} = \frac{37}{7} - \frac{13}{3} = \frac{111-91}{21} = \frac{20}{21}.

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