Six Sigma refers to achieving a process variability so small that the design specifications represent ___ standard deviations ab
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2^2 , or 4
since the exponents have the same base, we can subtract the exponent of the numerator by the exponent in the denominator.
So 2^-3 - 2^-5 = 2^(-3-(-5)) = 2^2
The new exponent is 2 because -3-(-5) is equal to 2.
since the exponents have the same base, we can subtract the exponent of the numerator by the exponent in the denominator.
So 2^-3 - 2^-5 = 2^(-3-(-5)) = 2^2
The new exponent is 2 because -3-(-5) is equal to 2.