Gray i don’t even think that is a shade dead
Answer:
Algebra :(
Step-by-step explanation:
Anyway haiiiiiiii remember me Katie i saw your question lol haiii
Answer:
mass on day 1: 3
mass on day 2: 9
mass on day 3: 27
Step-by-step explanation:
using this equation, y = 3^x, you can plug in 1, 2, and 3 for 'x' to get the value of 'y' (which represents the mass on specific days)
3^1 = 3
3^2 = 9
3^3 = 27
Givens: cos(q) = 3/5
Sin(2q) = 2 sin(q)*cos(q)
Step One
Find sin(q)
Sin(q)= sqrt(1 - cos^2(q) )
Sin(q) = sqrt(1 - (3/5)^2 ) = sqrt(1 - (9/25) = sqrt( (16/25) ) = 4/5. Because the angle is in the first quadrant, sin(q) > 0.
Step 2
Find the value of sin(2q)
sin(2q) = 2 sin(q) * cos(q)
Sin(2q) = 2* 3/5 * 4/5
sin(2q) = 24/25.
Note: you should notice that sin(2q) is less than 1 which is the way a sine function should behave.
Answer: Onggg frfr
Step-by-step explanation:
