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Drupady [299]
3 years ago
14

a nursery sells kentucky bluegrass seed for $5.75 per pound and tall fescue seed for $4.50 per pound. the nursery sells a mixtur

e of the two kinds of seed for $5.25 per pound. let k represent the amount of kentucky blue grass seed the nusery uses in in 5 pounds of the mixture
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
3 0

Answer:

k=3

Step-by-step explanation:

Given that:

Per pound cost of kentucky bluegrass seed = $5.75

Per pound cost of tall fescue seed = $4.50

Per pound cost of mixture of seeds = $5.25

k is the amount of kentucky blue grass.

Total amount of the mixture = 5 pounds

Therefore, amount of tall fescue seed = (5 - k) pounds

To find:

The value of k.

Cost of k pounds of kentucky bluegrass seed = \$5.75k

Cost of (5 - k) pounds of tall fescue seed = \$(5-k)4.50

As per question statement:

5.75k+(5-k)4.50=5.25\times 5\\\Rightarrow 575k+5\times 450 -450k=525\times5\\\Rightarrow 125k=75\times5\\\Rightarrow k =3\ pounds

Amount of kentucky blue grass seed used = <em>3 pounds</em>

Amount of tall fescue seed used = 5-3 = <em> 2 pounds</em>

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Annette [7]

Step-by-step explanation:

The company's jars of pickles weigh fewer than 68 ounces on average. C. The company's jars of pickles weigh more than 68 ounces on average. D. The company's jars of pickles do not weigh 68 ounces on average.

This is the Answer

4 0
3 years ago
A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

7 0
3 years ago
Is this rational or irrational I really need help ASAP! Will mark brainlist.
vichka [17]

Answer: Rational

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I hope this is good enough:

4 0
3 years ago
Write in terms of i . simplify your answer as much as possible. −99
Sonbull [250]
I^2 = -1
so,
-99 = -1*99 = i^2*99 = 99i^2
3 0
3 years ago
Factor the Polynomial: 20x³+34x²+6x = ?
Nataly_w [17]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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