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lapo4ka [179]
2 years ago
5

The city purchased 24 new buses that each hold 32 passengers. It also purchased 18 new smaller buses that each hold 27 passenger

s.
What is the greatest number of passengers that could be on all the new buses if all the seats were filled?
Mathematics
1 answer:
ioda2 years ago
5 0
24 buses....each holding 32 passengers.....24*32 = 768 passengers
18 smaller buses....each holding 27 passengers....18*27 = 486 passengers

for a total of : 768 + 486 = 1254 passengers <==
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5\sqrt[4]{x} or the fourth answer

Step-by-step explanation:

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Please *atleast* answer one of them!
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Answer and Step-by-step explanation:

*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^

1. Let's write out the equation to subtract.

7t - 2u - 3v - (t - 3v)

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6t - 2u

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6 0
2 years ago
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ramone has 5 difficult questions left to answer on a multiple choice test. Each question has 3 choices. For the first 2 of these
olchik [2.2K]
1. a b c
2. a b c
3. a b c
4. a b c
5. a b c

then she eliminated 1 choice in 1 and 2, say as follows

1.    b c
2. a b 
3. a b c
4. a b c
5. a b c

Probability of answering correctly the first 2, and at least 2 or the remaining 3 is 
P(answering 1,2 and exactly 2 of 3.4.or 5.)+P(answering 1,2 and also 3,4,5 )

P(answering 1,2 and exactly 2 of 3.4.or 5.)=
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also P(1,2,3,4 c, 5w)=P(1,2,3,5 c 4w)=P(1,2,4,5 c 3w )
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P(answering 1,2 and exactly 2 of 3.4.or 5.)=3*P(1,2,3,4)=3*1/2*1/2*1/3*1/3*2/3=1/4*2/9=2/36=1/18

note: P(1 correct)=1/2
         P(2 correct)=1/2
         P(3 correct)=1/3
         P(4 correct)=1/3
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P(answering 1,2 and also 3,4,5 )=1/2*1/2*1/3*1/3*1/3=1/108

Ans: P= 1/18+1/108=(6+1)/108=7/108
5 0
3 years ago
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