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Amiraneli [1.4K]

3 years ago

6

a group of 60 children went on a trip to the zoo 7/10 of the children had never been there how many children went to the zoo for

the first time

1 answer:

zvonat [6]3 years ago

5 0

Answer:

42

Step-by-step explanation:

as you divide 10 into 60 and then multiply it by 7 and your answer will be 42

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In May, Jim's lunch account has a balance of $58.19. If lunch costs 2.74 per day, how many days will Jim be able to buy lunch be

velikii [3]

He will be able to buy lunch for 21 days because 58.19 divided by 2.74 is 21. 237226

5 0

4 years ago

The new printer at the school is able to print 2,700 pages in 45 minutes. On average, how many pages does it print per minute?

garri49 [273]

Answer:

It can print 60 pages per minute.

Step-by-step explanation:

You would divide 2,700 by 45, to get your answer. 2,700÷45=60. So your answer will be 60 pages per minute.

8 0

4 years ago

Read 2 more answers

Write the equivalent logarithmic equation to 10^a = x+b

MA_775_DIABLO [31]

Answer:

The answer to your question is log₁₀ x + b = a

Step-by-step explanation:

General formula

Logarithmic function Exponential function

log ₐ b = c $b^{c} = a$

a = antilogaritm c = exponent

b = base b = base

c = logaritm a = power

In your problem

10 = base

a = exponent

x + b = power

Exponential function log₁₀ x + b = a

4 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

3 years ago

Another teacher has a monthly salary of $2000 She spends $943 per month on rent Her monthly salary then increases by 15% What pe

Aleks04 [339]

Answer:

47.15%

Step-by-step explanation:

Getting a raise of 15% would increase the teacher's salary by 300. 943 of 2300 is 47.15%.

5 0

2 years ago