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suter [353]
3 years ago
12

14

Mathematics
1 answer:
Ksivusya [100]3 years ago
6 0
One solution.

Hope that helps.
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What is the fifth term in the geometric sequence described by this explicit formula y=40×(-2)^(n-1)​
cupoosta [38]

Answer:

The fifth term is 620

Step-by-step explanation:

y=40×(-2)^(n-1)​

The 5th terms means n=5

y = 40 * (-2) ^ (5-1)

  = 40 * (-2) ^4

  = 40 * (16)

  = 640

5 0
3 years ago
Please help I’m stuck on this question!!
tatyana61 [14]

Answer:

says of the week

Step-by-step explanation:

x side or bottom of graph is independent variable

y side of left part of the graph is dependent variable

7 0
3 years ago
(Look at Screenshot)
Mkey [24]
Yes it’s school p just mind the mean
8 0
4 years ago
Some help I keep getting this freaking question wrong!!!!!
SpyIntel [72]

Okay, so there's 100 pennies in a dollar and 100 x 200 = 20,000

Then to find our amount of millimeters we need to do 20,000 x 1.55 = 31,000 millimeters = 31 meters

Hope it helps!

7 0
4 years ago
The scores on a Psychology exam were normally distributed with a mean of 67 and a standard deviation of 8. Create a normal distr
Trava [24]

Answer:

(a) The percentage of the scores were less than 59% is 16%.

(b) The percentage of the scores were over 83% is 2%.

(c) The number of students who received a score over 75% is 26.

Step-by-step explanation:

Let the random variable <em>X</em> represent the scores on a Psychology exam.

The random variable <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 67 and standard deviation, <em>σ</em> = 8.

Assume that the maximum score is 100.

(a)

Compute the probability of the scores that were less than 59% as follows:

P(X

                =P(Z

*Use a <em>z</em>-table.

Thus, the percentage of the scores were less than 59% is 16%.

(b)

Compute the probability of the scores that were over 83% as follows:

P(X>83)=P(\frac{X-\mu}{\sigma}>\frac{83-67}{8})

                =P(Z>2)\\\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the percentage of the scores were over 83% is 2%.

(c)

It is provided <em>n</em> = 160 students took the exam.

Compute the probability of the scores that were over 75% as follows:

P(X>75)=P(\frac{X-\mu}{\sigma}>\frac{75-67}{8})

                =P(Z>1)\\\\=1-P(Z

The percentage of students who received a score over 75% is 16%.

Compute the number of students who received a score over 75% as follows:

\text{Number of Students}=0.16\times 160=25.6\approx 26

Thus, the number of students who received a score over 75% is 26.

5 0
4 years ago
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