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abruzzese [7]
3 years ago
8

R2-44r+120= -30 + 11r Solve by factoring

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

r = 152/55

Step-by-step explanation:

122 - 44r = - 30 + 11r

122 - 44r - 11r = - 30

- 44r - 11r = - 30 - 122

- 55r = - 30 - 122

- 55r = - 152

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Select the correct answer from each drop-down menu.
o-na [289]

Answer:

The two grades that have a proportional relationship between the numbers of girls and boys are and grade 6 and 8

Step-by-step explanation:

Girls: Boys

9 : 12 (grade 6)

15 : 20 (grade 8)

3 : 4

4 0
3 years ago
g A sample of 3 items is chosen at random from a box containing 20 items, out of which 4 are defective. Let X be the number of d
professor190 [17]

Answer:

The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

P (X)=\frac{4}{20}=0.20

A random sample of <em>n</em> = 3 items are selected at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.

The variance of a Binomial distribution is:

V(X)=np(1-p)

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48

Compute the standard deviation (σ (X)) as follows:

\sigma (X)=\sqrt{V(X)}=\sqrt{0.48}=0.693

Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48

Compute the standard deviation of (20 - X) as follows:

\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693

Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

3 0
3 years ago
Solve x: <br> 6 - x/10 = -3<br> -Please Help! Homework due in for Monday Xx
Rom4ik [11]
6 - x/10 = -3
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9 = x/10
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3 years ago
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For a quadrilateral to be a square, the diagonals must be ________________.
Lynna [10]

Answer:

That bisect and are perpendicular

Step-by-step explanation:

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2 years ago
(8n+1)(6n-3) please solve in quadratic formula
cestrela7 [59]
Use the distributive property.

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