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3 years ago

5

I neeed helpppppp pleaseeeeee

2 answers:

GalinKa [24]3 years ago

7 0

15^2 is the answer to ur question

zhenek [66]3 years ago

3 0

Answer:

its 15 to the square root of 2

Step-by-step explanation:

You might be interested in

In the past, 21% of all homes with a stay-at-home parent, the father is the stay-at-home parent. An independent research firm ha

Afina-wow [57]

Answer:

A sample size of 79 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$\pi = 0.21$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.09?

A sample size of n is needed.

n is found when M = 0.09. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.09 = 1.96\sqrt{\frac{0.21*0.79}{n}}$

$0.09\sqrt{n} = 1.96\sqrt{0.21*0.79}$

$\sqrt{n} = \frac{1.96\sqrt{0.21*0.79}}{0.09}$

$(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.21*0.79}}{0.09})^{2}$

$n = 78.68$

Rounding up to the nearest whole number.

A sample size of 79 is needed.

4 0

3 years ago

Mrs.Lamb’s favorite candy bar weight 3 ounces. If a box contains 150 of these candy bars, what is the weight, In pounds, of this

Bumek [7]

Answer:

28.125

Step-by-step explanation:

A bar weights 3 ounces, she has a box of 150 so you multiply

150 times 3 = 450

well one pound equals 16 ounces, so you divide

450 divide by 16 = 28.125

5 0

2 years ago

If x is 1 what is the value of y?9x - 5y = 29

mylen [45]

Given

The equation,

9x - 5y = 29.

To find the value of y when x is 1.

Explanation:

It is given that,

$9x-5y=29$

That implies,

When x=1,

$\begin{gathered} 9(1)-5y=29 \\ 9-5y=29 \\ -5y=29-9 \\ -5y=20 \\ y=\frac{20}{-5} \\ y=-4 \end{gathered}$

Hence, the value of y is -4.

4 0

1 year ago

Integers contain whole numbers True or False

murzikaleks [220]

Answer:

true...integers are whole number...both negative and positive

Step-by-step explanation:

4 0

3 years ago

A football player is running the length of a 100 yard long football field. For the first part of the field, he runs at a rate of

notka56 [123]

Answer:

$\frac{2}{5}$ th part of the field is covered in the second sprint.

Step-by-step explanation:

A football player is running the length of a 100 yard long football field.

Let player sprints x yards with the speed = 2 yards per second.

So time taken to cover x yards player will take time = $\frac{x}{2}$ seconds

Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = $\frac{Distance}{Speed}$

= $\frac{100-x}{4}$ seconds

Now total time taken by the player can be represented by the equation

$\frac{x}{2}+\frac{100-x}{4}=40$

Now we can solve this equation for the value of x.

$\frac{2x+100-x}{4}=40$

x + 100 = 40×4

x + 100 = 160

x = 160 - 100 = 60 yards

And length of the second part will be = 100 - 60 = 40 yards

Now the fraction of the field covered by the player in second sprint will be

= $\frac{40}{100}$

= $\frac{2}{5}$ or 40%

Therefore, $\frac{2}{5}$ th part of the field was covered in second sprint.

5 0

3 years ago