The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
<h3>How to determine the intersection of the lines?</h3>
The lines are given as:
y = -14x + 3 and y = -32x+3
Substitute y = -32x+3 in
-32x+3 = -14x + 3
Evaluate the like terms
-18x = 0
Divide by -18
x = 0
Substitute x = 0 in y = -14x + 3
y = -14(0) + 3
Evaluate
y = 3
Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
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In the problem, two legs measurement were given such as:
Leg 1 = 12 inches
Leg 2 = 15 inches
We need to solve for the third leg. Since it is a right triangle, we can use Pythagorean theorem in solving the missing leg:
c²=b²+a²
When we assume that the third leg is the "c", we can for the value such as:
c² = 12²+15²
c=19.21
When we assume that the third is either "a" or "b":
15² =a² + 12²
a=9
Then, the possible measurement of the third leg is 9 or 19.21.
The difference between the two possible answer is shown below:
Difference = 19.21 -9 = 10.21
Difference =10.21
Answer:
q = 26
Step-by-step explanation:
Given the point (3, q ) lies on the line then the coordinates satisfy the equation.
Substitute x = 3, y = q into the equation
q = 8(3) + 2 = 24 + 2 = 26
He’s 41 now
just add 5 to his age