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2 years ago

The velocity of a moving body is given by the equation V = 12t – 6t2. For what

Mathematics

1 answer:

Alex787 [66]2 years ago

7 0

Answer:

greatest velocity 6

Step-by-step explanation:

v=12t-6t2

dv/dt=0

12-12t=0

t=1

v at t=1=12-6=6

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Find the formula for the nth term of the sequence: 0,7,18,33,52

defon

Answer:

t(n) = 2n² + n - 3

Step-by-step explanation:

Given sequence:

0, 7, 18, 33, 52

Find the formula for nth term t(n)

<h3>Solution</h3>

Sequence is neither arithmetic nor geometric, analyzing:

0, 7, 18, 33, 52

First level difference

7, 11, 15, 19

Second level difference

4, 4, 4

As there are two levels, the formula should be in the form of:

t(n) = an² + bn + c

Trying the formula with the known terms:

t(1) = 0 ⇒ a+b + c= 0

t(2) = 4a + 2b + c = 7 ⇒ 3a + b = 7

t(3) = 9a + 3b + c = 18 ⇒ 3(3a+b) + c = 18 ⇒ 21 + c = 18 ⇒ c = -3

Going back to previous equations to find remaining coefficients:

t(1) ⇒ a+ b = 3 ⇒ t(2) = 2a + (a+b) = 7 ⇒2a + 3 = 7 ⇒ a= 2 ⇒ b = 1

So the formula becomes:

t(n) = 2n² + n - 3

8 0

3 years ago

A plane flies 35 km in the direction n 30° w, then flies 60 km in the direction n 60° e. how far is the plane from its original

Kipish [7]

The distance of plane from the starting point is 69.46 km.

Given that the plane first flies 35 km in the direction N30W and then 60 km in the direction N60E.

We have to find the distance of plane from starting point.

We have to use pythagoras theorem in this which says that the square of hypotenuse is equal to sum of squares of the base and perpendicular.

$H^{2} =P^{2} +B^{2}$

From the figure we can say that P=35 km .and B=60 km

In this we have to find the value of H when P=35 and B=60

$H^{2} =35^{2} +60^{2}$

$H^{2}$ =1225+3600

$H^{2}$ =6946

H=69.46

Hence the distance of plane from starting point is 69.46 km.

Learn more about pythagoras theorem at brainly.com/question/343682

#SPJ4

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2 years ago