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Delvig [45]
2 years ago
11

The equation for Constant of Proportionality is y = kx? If you solved for the letter k instead of y, would the correct equation.

be y/x = k? YES or NO
Mathematics
1 answer:
telo118 [61]2 years ago
3 0
I don’t think it would work it you solved for k instead of y. Because you’re solving for y when you do constant of proportionality. i’m not sure if i’m right or not but that’s what i think.
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Answer:

T represents the amount of time it will take him to travel 200 meters if he swims at 45 meters per minute.

Step-by-step explanation:

4 0
3 years ago
Could someone help here, thankyou!
ludmilkaskok [199]

Answer:

x = 6 cm

Step-by-step explanation:

Given ratio of sides of similar figures = a : b , then

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Here ratio of areas = 5 : 45 = 1 : 9 , so

ratio of sides = \sqrt{1} : \sqrt{9} = 1 : 3

Thus side of B is 3 times side of A

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2 years ago
SAT verbal scores are normally distributed with a mean of 433 and a standard deviation of 90. Use the Empirical Rule to determin
laila [671]

34% of the scores lie between 433 and 523.

Solution:

Given data:

Mean (μ) = 433

Standard deviation (σ) = 90

<u>Empirical rule to determine the percent:</u>

(1) About 68% of all the values lie within 1 standard deviation of the mean.

(2) About 95% of all the values lie within 2 standard deviations of the mean.

(3) About 99.7% of all the values lie within 3 standard deviations of the mean.

$Z(X)=\frac{x-\mu}{\sigma}

$Z(433)=\frac{433-\ 433}{90}=0

$Z(523)=\frac{523-\ 433}{90}=1

Z lies between o and 1.

P(433 < x < 523) = P(0 < Z < 1)

μ = 433 and μ + σ = 433 + 90 = 523

Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.

i. e. ((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%

Here μ to μ + σ = \frac{68\%}{2} =34\%

Hence 34% of the scores lie between 433 and 523.

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What is not an acceptable form of proof
STALIN [3.7K]
No reason, or no evidence to support your claim/proof
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