Question

Jackie is practicing free throws after basketball practice. She makes a free throw shot with probability 0.7. She takes 20 shots. We say that making a shot is a success. What are p,q, and n in this context? Select the correct answer below: a.p=0.7, q = 0.7, n = 20 b.p=0.3, q 0.7, n = 20 c.p-0.3, q = 0.6, n " 20 0 0.7, q = 0.3, 20 p d. p:0.7, q =0.1,n=20

Answer 1

Answer:

n = 20 q = 0.7, q = 0.3

Step-by-step explanation:

For each shot that she takes, there are only two possible outcomes. Either she makes or, she does not make is. The probability of making each shot is independent from other shots. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

We also ahve that q = 1-p.

Jackie is practicing free throws after basketball practice. She makes a free throw shot with probability 0.7.

This means that $p = 0.7$ and $q = 1-p = 0.3$

She takes 20 shots.

This means that $n = 20$

So the correct answer is:

n = 20 q = 0.7, q = 0.3